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ValentinkaMS [17]
3 years ago
7

A bicyclist steadily speeds up from rest to 11.0m/s during a 5.50s time interval. Determine all unknowns and answer the followin

g questions. What is the magnitude of the bicyclist's acceleration? How far did the bicyclist travel during this time?
Physics
1 answer:
Marina86 [1]3 years ago
5 0

Explanation:

acceleration is 2 m/s^2

v-u/t

distance travelled is 30.25 meter

(v^2-u^2)/2a

11*11/2*2

121/4

30.25 m

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You stand on a straight desert road at night and observe a vehicle approaching. This vehicle is equipped with two small headligh
choli [55]

Answer:

They can be seen from a distance of 4.372 kilometers.

Explanation:

Using the Reyligh creterion for diffraction through a circular aperture we have

\frac{x}{D}=\frac{1.22\lambda }{d}

where symbol's have their usual meaning

thus applying values we get

D=\frac{dx}{1.22\lambda }

\therefore D=\frac{0.633\times 4.61\times 10^{-3}}{1.22\times 547\times 10^{-9}}\\\\D=4372.77m\\=4.372km

5 0
3 years ago
Which is heavier , 1kg of steel or i kg of cork​
goblinko [34]

Answer:

Same weight so neither is heavier

6 0
3 years ago
Read 2 more answers
Can someone help me with this I don’t understand how to do this
olga nikolaevna [1]

Answer:

You are doing this wrong. Make sure that if you have 2 rows and on the top it has pounds then on the second bottom row you also have pounds so that they cancel each other out.

Explanation:

4 0
3 years ago
The dispatcher of courier service receives a message from truck A that reports a position of +5 after a displacement of +2. What
Romashka [77]

The formula we need to use is displacement.

d=\Delta{x}=x_f-x_i, where xf is final position and xi is initial position.

We report the final position of 5 and the displacement of 2 so the formula is now:

2=5-x_i\Longrightarrow x_i=3.

So the initial position of truck A is 3.

Hope this helps.

r3t40

8 0
3 years ago
Consider an e. coli to be a cylinder with a diameter of 1 micrometer (um) and with a length of 2 micrometer (um).
julia-pushkina [17]

Answer:

A=6.28\ \mu m^2

Part 1

V=1.57 \ \mu m^3

Part 2

A=6.28\ \mu m^2

Explanation:

Given that

Diameter,d=1 μm

Length ,l=2 μm

As we know that volume of cylinder given as

V=\pi r^2l

V=\pi \times 0.5^2\times 2 \ \mu m^3

V=1.57 \ \mu m^3

Surface area,A

A=π d l

A=\pi \times 1 \times 2\ \mu m^2

A=6.28\ \mu m^2

Part 1

V=1.57 \ \mu m^3

Part 2

A=6.28\ \mu m^2

4 0
4 years ago
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