Answer:
(a) The magnitude of the electric dipole moment is 1.68 x 10⁻¹⁴ C.m
(b) The difference between the potential energies ΔU, is 4.6704 x 10⁻¹¹ J
Explanation:
Given;
magnitude of charge, q = 2 nC = 2 x 10⁻⁹ C
distance of separation, d = 8.4 μm = 8.4 x 10⁻⁶ m
strength of electric field, E = 1390 N/C
(a) the magnitude of the electric dipole moment
p = qd
p = (2 x 10⁻⁹ C)(8.4 x 10⁻⁶ m)
p = 1.68 x 10⁻¹⁴ C.m
(b) the difference between the potential energies for dipole orientations parallel and anti-parallel to E
ΔU = U(180) - U(0)
ΔU = 2pE
ΔU = 2(1.68 x 10⁻¹⁴ )(1390)
ΔU = 4.6704 x 10⁻¹¹ J
Answer: Accelaration is 2.77 m/s*s
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Explanation:
V0=0km/h=0m/s
V1=100 km/h=27.7 m/s
t=10s=
Use equation for accelaration : a=(V1-V0)/t
a=(0m/s-27.7m/s)/10s
a=-27.7s/10s
a=2.77m/s*s
Give the mathematical expression for coulomb's force if q1, q2 are the magnitude of charges and r is the distance between them.
F=K q1q2/r2
Answer:
To solve this problem we will apply the principle of conservation of energy for which we have that the potential energy on a body, is equivalent to the work done on it at the given point. Therefore we will have the following equality
At the same time we know that work is equivalent to the Force applied over a given distance, so,
The potential energy is equivalent to the product between mass, gravity and height. Recall that the product of mass and gravity is equivalent to weight (The same given in the statement)
Equating,
Then,
Replacing,
Therefore the force needed to lift the piano is 600N
Explanation:
HOPE THIS HELPS!!!
What is the question? I think that you answered it yourself...
