Write in slope intercept form an equation of the line that passes through the given points

Find the general solution of the following ODE: y' + 1/t y = 3 cos(2t), t > 0.

Margarita [4]

Answer:

y = 3sin2t/2 - 3cos2t/4t + C/t

Step-by-step explanation:

The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt

Comparing the standard form with the given differential equation.

p(t) = 1/t and q(t) = 3cos(2t)

I = e^∫1/tdt

I = e^ln(t)

I = t

The general solution for first a first order DE is expressed as;

y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.

yt = ∫t(3cos2t)dt

yt = 3∫t(cos2t)dt ...... 1

Integrating ∫t(cos2t)dt using integration by part.

Let u = t, dv = cos2tdt

du/dt = 1; du = dt

v = ∫(cos2t)dt

v = sin2t/2

∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt

= tsin2t/2 - cos2t/4 ..... 2

Substituting equation 2 into 1

yt = 3(tsin2t/2 - cos2t/4) + C

Divide through by t

y = 3sin2t/2 - 3cos2t/4t + C/t

Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t

3 0

3 years ago

The tea chest needs to send the sales tax that it has collected to the state. The total sales, including 4% sales tax are $7115.

Elina [12.6K]

.04*7115.68=284.6272

$284.62 or $284.63 (depending on how lenient your teacher is with rounding)

8 0

3 years ago

The area of rectangular field is 1440 sq meters and perimeter is 152 metre. Out of length or breadth which one is to be decrease

Arturiano [62]

Answer:

If Length is decreased by 10% then it would become a square.

Step-by-step explanation:

Given:

Area of Rectangular field = 1440 sq. m

Perimeter = 152 m.

We need to find which one needs to be decreased by what percentage to make it a square.

Solution:

Let length be denoted by 'l'.

Also Let width be denoted by 'w'.

Now we know that Area of rectangular field is given by Length times width.

framing in equation form we get;

$l\times w = 1440 \ \ \ \ equation\ 1$

Also we know that Perimeter of rectangular field is given by 2 times sum of Length and width.

framing in equation form we get;

$2(l+w) =152\\\\l+w =\frac{152}{2}\\\\l+w=76\\\\l=76-w \ \ \ \ equation \ 2$

Now Substituting equation 2 in equation 1 we get;

$l\times w =1440\\\\(76-w)w=1440\\\\76w-w^2=1440\\\\w^2-76w+1440 =0$

Now we will find the root by factorizing the same we get;

$w^2-36w-40w+1440=0\\\\w(w-36)-40(w-36)=0\\\\(w-36)(w-40) =0 \\$

Now solving for each to find the value of 'w' we get;

$w-36 =0\\\\w=36\\\\also \\\\w-40=0\\\\w=40$

So We can say that;

Width = 36 m and Length = 40 m

Now we need to find out of length or breadth which one is to be decreased by what percentage to make it a square.

We know that square has all sides same.

So from the data we found we can say that if length is decreased by 4 then length and breadth(width) both will be equal.

So to find percentage decreased we will divide length to be decreased by total length and then multiply by 100.

framing in equation form we get;

percentage decreased = $\frac{4}{40}\times 100 = 10\%$

Hence If Length is decreased by 10% then it would become a square.

6 0

3 years ago

The sum of x and 3/5 is 5/7.

crimeas [40]

We first write the word in math as x+3/5 = 5/7. Now we cross multiply our fractions and rewrite them with the LCD of 5 and 7. Our equation now looks like x + 21/35 = 25/35. We simplify our equation by subtracting 21/35 from both sides to get x = 4/35. 4/35 is already in lowest terms so it is our answer.

7 0

3 years ago

Read 2 more answers

Given the equation given D=M/V if D=2/3 and v = m + 1, then m is what?

VARVARA [1.3K]

Answer:

2

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers