Find the measure of the missing angles. Both of them is wrong. (Picture included)

Mathematics

1 answer:

Ymorist [56]2 years ago

6 0

Answer: you need to add them together then add BAND D to the same expersion

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Find the solution of the square root of the quantity of x plus 2 plus 4 equals 8, and determine if it is an extraneous solution

Iteru [2.4K]

Consider the equation:

$\sqrt{x+2}+4 = 8$

Subtracting '4' from both the sides of the equation, we get as

$\sqrt{x+2}+4-4= 8-4$

$\sqrt{x+2}= 4$

Squaring on both the sides of the equation, we get

$(\sqrt{x+2})^2 = (4)^2$

$x+2 = 16$

Subtracting '2' from both the sides of the equation, we get

$x+2-2=16-2$

x=14

Since, An extraneous solution is a solution that arises from the solving process that is not really a solution at all. But, in this equation x=14 is the solution of the given equation.

Hence, it is not an extraneous solution.

4 0

3 years ago

Read 2 more answers

PLESE HELP GEOMETERY

nalin [4]

In this problem, you must use SohCahToa which basically means:

Sin - opposite over hypotenuse

Cosine - adjacent over hypotenuse

Tangent - Opposite over hypotenuse

So in this picture we have 4 -which is on the opposite side of x - and a 5 -which is the hypotenuse of the triangle. This means we must use sin.

Using a calculator you put in:

$sin^{-1} (\frac{4}{5} )$