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labwork [276]
2 years ago
12

Help me pleaseee I need it!​

Chemistry
1 answer:
sashaice [31]2 years ago
8 0
They have the most moons because they have the most mass
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What is the empirical formula of a compound that contains 6.10 g of hydrogen and 28 g of nitrogen?
Viktor [21]

Answer:

NH₃

Explanation:

mass H = 6.10 grams

mass N = 28.00 grams

mass cpd = (6.10 + 28.00)grams = 34.10 grams

%H/100wt = (6.10/34.10)100% = 17.9% w/w

%N/100wt = (28.00/34.1)100% = 82.1% w/w

%/100wt => grams/100wt => moles => ratio => reduce => emp ratio

%H/100wt = 17.9% w/w => 17.9g => (17.9/1)moles = 17.9 moles H

%N/100wt = 82.1% w/w => 82.1g => (82.1/14)moles = 5.9 moles N

Ratio N:H => 17.9 : 5.9

Reduce mole ratio (divide by smaller mole value) => 17.9/5.9 : 5.9/5.9

=> 3HY:1H empirical ratio => empirical formula NH₃ (ammonia)

3 0
3 years ago
How many valence electrons are in a silicon atom?
vladimir1956 [14]
Four valence electron
4 0
3 years ago
2 moles of substance A contains 12.04 × 1023 atoms.
professor190 [17]

Answer:

2 moles of Substance B

Explanation:

Because 1 mole of any substance contains 6.02× 10²³ particles either atoms, molecules, ions or even electron(Avogardo Constant)

Therefore 12.04 × 10²³/ 6.02× 10²³  =  2 mole of Substance B

7 0
2 years ago
(Pls help i will give brainlyest) Label the missing parts of the diagram.
WARRIOR [948]

Answer:

                                 Sedimentary rock

Metamorphic rock                                 Igneous rock

4 0
2 years ago
A trial of this decomposition experiment, using different quantities of reactants than those listed in the question above produc
Paul [167]

Answer : The volume of O_2(g) produced at standard conditions of temperature and pressure is 0.2422 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of O_2 gas = (740-22.4) torr = 717.6 torr

P_2 = final pressure of O_2 gas at STP= 760 torr

V_1 = initial volume of O_2 gas = 280 mL

V_2 = final volume of O_2 gas at STP = ?

T_1 = initial temperature of O_2 gas = 25^oC=273+25=298K

T_2 = final temperature of O_2 gas = 0^oC=273+0=273K

Now put all the given values in the above equation, we get:

\frac{717.6torr\times 280mL}{298K}=\frac{760torr\times V_2}{273K}

V_2=242.2mL=0.2422L

Therefore, the volume of O_2(g) produced at standard conditions of temperature and pressure is 0.2422 L

5 0
3 years ago
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