When ΔG° is the change in Gibbs free energy
So according to ΔG° formula:
ΔG° = - R*T*(㏑K)
here when K = [NH3]^2/[N2][H2]^3 = Kc
and Kc = 9
and when T is the temperature in Kelvin = 350 + 273 = 623 K
and R is the universal gas constant = 8.314 1/mol.K
So by substitution in ΔG° formula:
∴ ΔG° = - 8.314 1/ mol.K * 623 K *㏑(9)
= - 4536
NaHCO3 is the right answer
Interphase is not a phase of mitosis.
Answer:

Explanation:
We are given the mass, specific heat, and temperature, so we must use this formula for heat energy.

The mass is 5 grams, the specific heat capacity is 0.14 Joules per gram degree Celsius. Let's find the change in temperature.
- ΔT= final temperature - initial temperature
- ΔT= 95°C - 15°C = 80°C
We know the variables and can substitute them into the formula.


Multiply the first numbers. The grams will cancel.

Multiply again. This time the degrees Celsius cancel.

56 Joules of heat are needed.
Answer:
Yes
Explanation:
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