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galina1969 [7]
3 years ago
5

What is the molecular formula of a compound if it’s empirical

Chemistry
1 answer:
snow_lady [41]3 years ago
4 0
Depends on what compound we’re talking about here
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What is the atomic number of the as yet undiscovered element in which the 8s and 8p electron energy levels?
Andreyy89

The atomic number of the undiscovered element is 168

Element 118 will have just filled its 7p orbitals. therefore the predicted element to fill completely up to its 8 p orbital would have to filled a whole set of s, p, d, f and g orbitals

That's another 2 + 6 + 10 +14 + 18 = 50 electrons

To determine the total number of quantum numbers we have to find

Nml × Nms

we have Nml × Nms = ( 2 + 1 ) × 2

8s + 8P + 7d + 6f + 5g = 2 + 6 + 10 + 14 + 18 = 50

The element right below should be

Z = 118 + 50

   = 168

Hence the atomic number of the undiscovered element is 168

Learn more about the atomic number on

brainly.com/question/14514242

#SPJ4

4 0
1 year ago
Sugar dissolved completely in water to form a solution. The solution is a ?<br><br> pleasee help
aksik [14]

Answer:

the mixture or solution is called homogeneous mixture

4 0
3 years ago
PLEASE PLEASE HELP!
valentinak56 [21]

Answer: The number of grams of H_2 in 1620 mL is 1.44 g

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1 atm (at STP)

V = Volume of gas = 1620 ml = 1.62 L  (1L=1000ml)

n = number of moles = ?

R = gas constant =0.0821Latm/Kmol

T =temperature =273K

n=\frac{PV}{RT}

n=\frac{1atm\times 16.2L}{0.0821Latm/K mol\times 273K}=0.72moles

Mass of hydrogen =moles\times {\text {Molar mass}}=0.72mol\times 2g/mol=1.44g

The number of grams of H_2 in 1620 mL is 1.44 g

8 0
3 years ago
The volume of 5.00 M KBr needed to have 1.00 mol KBr mL
astra-53 [7]

Answer: molarity = mole solute/ liter of solution.

=> volume= mole/molarity = 1/5 = 0.2 L = 200mL

Explanation:

7 0
3 years ago
C= ( F - 32) / 1.8<br> 86 F = ?
egoroff_w [7]

<h3>⇒c =  \frac{f - 32}{1.8}</h3><h3>⇒c =  \frac{86 - 32}{1.8}</h3><h3>⇒c =  \frac{54}{1.8}</h3><h3>⇒c = 30</h3>

<em>Hence</em><em>,</em><em> </em><em>84</em><em>°</em><em>F</em><em> </em><em>is</em><em> </em><em>30</em><em>°</em><em>C</em><em> </em><em>in</em><em> </em><em>Celsius</em><em>.</em><em>.</em>

7 0
2 years ago
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