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castortr0y [4]
3 years ago
11

An unknown gas effuses 1.66 times more rapidly than CO2. What is the molar mass of the unknown gas, given that the molar mass of

CO2 is 44 grams?
Chemistry
2 answers:
Y_Kistochka [10]3 years ago
4 0
The molar mass is 16.0 grams 
Soloha48 [4]3 years ago
3 0
To determine the molar mass of the unknown gas, we use Graham's Law of effusion which relates the rate of the gases with their respective molar masses. We calculate as follows:

r1 / r2 = √(M2 / M1 )

We let 1 represent the unknown gas and 2 the carbon dioxide.

r1 / r2 = 1.66 = √(44.01 / M1 )
M1  = 15.97 g/mol
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Explanation:

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rjkz [21]
Your answer is correct.

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A student sees an absorbance a=1.140 for his solution that has a concentration of c=1.50*10-4 m using 0.50 cm cuvette. what is t
777dan777 [17]

The molar extinction coefficient is 15,200 M^{-1} cm^{-1}.

The formula to be used to calculate molar extinction coefficient is -

A = ξcl, where A represents absorption, ξ refers molar extinction coefficient, c refers to concentration and l represents length.

The given values are in required units, hence, there is no need to convert them. Directly keeping the values in formula to find the value of molar extinction coefficient.

Rewriting the formula as per molar extinction coefficient -

ξ = \frac{A}{cl}

ξ = \frac{1.140}{1.5*10^{-4}*0.5 }

Performing multiplication in denominator to find the value of molar extinction coefficient

ξ = \frac{1.140}{0.000075}  

Performing division to find the value of molar extinction coefficient

ξ = 15,200 M^{-1} cm^{-1}

Hence, the molar extinction coefficient is  15,200 M^{-1} cm^{-1}.

Learn more about molar extinction coefficient -

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6 0
1 year ago
If a gas has a volume of 1000 ML at a temperature of 23°C and a pressure of 100 mmhg, what is it’s volume under standard conditi
Colt1911 [192]

Answer:

119.7 mL.

Explanation:

  • From the general law of ideal gases:

<em>PV = nRT.</em>

where, P is the pressure of the gas.

V is the volume of the container.

n is the no. of moles of the gas.

R is the general gas constant.

T is the temperature of the gas (K).

  • For the same no. of moles of the gas at two different (P, V, and T):

<em>P₁V₁/T₁ = P₂V₂/T₂.</em>

  • P₁ = 100.0 mmHg, V₁ = 1000.0 mL, T₁ = 23°C + 273 = 296 K.
  • P₂ = 1.0 atm = 760.0 mmHg (standard P), V₂ = ??? mL, T₂ = 0.0°C + 273 = 273.0 K (standard T).

<em>∴ V₂ = (P₁V₁T₂)/(T₁P₂) </em>= (100.0 mmHg)(1000.0 mL)(273.0 K)/(296 K)(760.0 mmHg) =  121.4 <em>mL.</em>

8 0
3 years ago
What is a nonpolar covalent bond?
Vlad1618 [11]

<u>Answer:</u> The correct answer is Option D.

<u>Explanation:</u>

A non-polar covalent bond is defined as the bond which is formed between the atoms having no difference in electronegativity values. For Example: Cl_2,H_2 etc..

In this bond, the electrons are shared equally and \Delta EN value is equal to 0.

Hence, the correct answer is Option D.

8 0
3 years ago
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