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MaRussiya [10]
1 year ago
9

co3 forms a more stable complex with the chelating ligand en (h2nch2ch2nh2) than it does with the monodentate ligand methylamine

(ch3nh2). what is the reason that [co(en)3]3 is more stable than [co(ch3nh2)6]3 ?
Chemistry
1 answer:
wariber [46]1 year ago
5 0

[CO(en)₃]³⁺   is more stable than [CO(CH₃NH₂)]³⁺ to make more stable complex because of chelate effect.

[CO(en)₃]³⁺  is a metal chelate due to presece of bidentate ligand ethylene diamine ligand. Metal chelates are more stable than complexes containing only monodentate ligands because of the chelate effect, we expect ethylenediamine to form a stronger complex with Co than ammonia.

The Chelate Effect is that complexes resulting from coordination with the chelating ligand is much more thermodynamically stable than complexes with non-chelating ligands.

The chelate effect defined as  the augmented affinity of chelating ligands for any metalic ion in comparison of the affinity of a similar nonchelating ligands for the same metallic ion.

learn more about chelate effect at brainly.com/question/15242975

#SPJ4

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A gas will stay dissolved in solution best
m_a_m_a [10]
A. (cold solutions hold on to their solutes better)
5 0
3 years ago
2. Chromium+oxygen - chromium(III) oxide <br>balanced​
sesenic [268]

Answer:

4Cr + 3O2 —> 2Cr2O3

Explanation:

Information from the question include:

Chromium + oxygen -> chromium(III) oxide

From the word equation given above, the equation can be written as follow:

Cr + O2 —> Cr2O3

The equation can be balance by doing the following:

There are 2 atoms of O on the left side and 3 atoms on the right side. It can be balance by putting 2 in front of Cr2O3 and 3 in front of O2 as shown below:

Cr + 3O2 —> 2Cr2O3

Now, we have 4 atoms of Cr on the right side and 1 atom on the left. It can be balance by putting 4 in front of Cr as shown below:

4Cr + 3O2 —> 2Cr2O3

Now the equation is balanced

3 0
3 years ago
If the car still produces 8500N, but now it accelerates at only 4 m/s2 what is the MASS
Mashutka [201]

Answer:

You can do that yourself, but there's a example question below. And, if for example, I just answer your question and you don't even try to answer. it dosent matter.

Explanation:Force=Mass x Acceleration  -or-  F=ma

where F is the force, m is the mass, and a is the acceleration. The units are Newtons (N) for force, kilograms (kg) for mass, and meters per second squared (m/s2) for acceleration. The other forms of the equation can be used to solve for mass or acceleration.

m=F/a and a=F/m Example:

Engineers at the Johnson Space Center must determine the net force needed for a rocket to achieve an acceleration of 70 m/s2. If the mass of the rocket is 45,000 kg, how much net force must the rocket develop?

Using Newton's second law, F=ma

F=(45,000 kg)(70 m/s2) = 3,150,000 kg m/s2 F=3,150,000 N Note that the units kg m/s2 and newtons are equivalent; that is, 1 kg m/s2

6 0
3 years ago
When an irregularly shaped chunk of an unknown metal with a mass of 25.32 g was placed in a graduated cylinder containing 25.00
inn [45]

Answer: The density of the unknown metal is 7.86 g/ml.

Explanation:

Density is defined as the mass contained per unit volume.

Density=\frac{mass}{Volume}

Given : Mass of metal  = 25.32 g

Volume of metal = volume of water displaced = (28.22 - 25.00) ml = 3.22 ml

Putting in the values we get:

density=\frac{25.32g}{3.22ml}

Density=7.86g/ml

Thus the density of the unknown metal is 7.86 g/ml

7 0
3 years ago
Solution A is 0.44 M and reacts with 0.11 M of solution B. Assume that the value of x is 0, the value of y is 1, and r is 1.07 ×
xz_007 [3.2K]

Answer:

K, the rate constant = 9.73 × 10^(-1)/s

Explanation:

r = K × [A]^x × [B]^y

r = Rate = 1.07 × 10^(-1)/s

K = Rate constant

A and B = Concentration in mol/dm^-3

A = 0.44M

B = 0.11M

x = Order of reaction with respect to A = 0

y = Order of reaction with respect to B = 1

Solving, we get

r/([A]^x × [B]^y) = K

K = 1.07 × 10^(-1)/s/(0.44^0 × 0.11^1)= 0.9727

K = 0.9727

7 0
3 years ago
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