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MaRussiya [10]
1 year ago
9

co3 forms a more stable complex with the chelating ligand en (h2nch2ch2nh2) than it does with the monodentate ligand methylamine

(ch3nh2). what is the reason that [co(en)3]3 is more stable than [co(ch3nh2)6]3 ?
Chemistry
1 answer:
wariber [46]1 year ago
5 0

[CO(en)₃]³⁺   is more stable than [CO(CH₃NH₂)]³⁺ to make more stable complex because of chelate effect.

[CO(en)₃]³⁺  is a metal chelate due to presece of bidentate ligand ethylene diamine ligand. Metal chelates are more stable than complexes containing only monodentate ligands because of the chelate effect, we expect ethylenediamine to form a stronger complex with Co than ammonia.

The Chelate Effect is that complexes resulting from coordination with the chelating ligand is much more thermodynamically stable than complexes with non-chelating ligands.

The chelate effect defined as  the augmented affinity of chelating ligands for any metalic ion in comparison of the affinity of a similar nonchelating ligands for the same metallic ion.

learn more about chelate effect at brainly.com/question/15242975

#SPJ4

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Which formulas could represent the empirical formula and the molecular formula of a given compound?
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Answer:

d

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d

7 0
2 years ago
The solubility of acetanilide is 12.8 g in 100 mL of ethanol at 0 ∘C, and 46.4 g in 100 mL of ethanol at 60 ∘C. What is the maxi
weqwewe [10]

Answer: 72.41% and 26.90% respectively.

Explanation:

At 60°C, you can dissolve 46.4g of acetanilide in 100mL of ethanol. If you lower the temperature, at 0°C, you can dissolve just 12.8g, which means (46.4g-12.8g)=33.6g of acetanilide must have precipitated from the solution.

We can calculate recovery as:

\%R=\frac{crystalized\ mass}{initial\ mass}*100 =\frac{33.6\ g}{46.4\ g}*100=72.41\%

So the answer to the first question is 72.41%.

For the second part just use the same formula, the mass of the precipitate is the final mass minus the initial mass, (171mg-125mg)=46mg.

\%R=\frac{crystalized\ mass}{initial\ mass}*100 =\frac{46\ mg}{171\ mg}*100=26.90\%

So the answer to the second question is 26.90%.

3 0
2 years ago
For each pair, choose the compound with the smaller lattice energy, and explain your choice: (b) K₂O or K₂S.
dlinn [17]

the compound with the smaller lattice energy is potassium sulphide here the size of the molecule play a important role

The quantity of energy released by the electrostatic attraction of oppositely charged ions is known as lattice energy (L.E). The ion's size and charge affect the lattice energy.

lattice energy is inversely proportional to   size of ion and directly proportional to charge of the ion. They are each charged equally that is plus two and minus two However, because the Sulphur is larger in size  and the oxygen is lesser in this case, The lattice energy of potassium oxide is larger  the lattice energy of potassium sulphide  is smaller.

To learn more about lattice energy :

brainly.com/question/18222315

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5 0
1 year ago
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Zepler [3.9K]

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2 years ago
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