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MaRussiya [10]
1 year ago
9

co3 forms a more stable complex with the chelating ligand en (h2nch2ch2nh2) than it does with the monodentate ligand methylamine

(ch3nh2). what is the reason that [co(en)3]3 is more stable than [co(ch3nh2)6]3 ?
Chemistry
1 answer:
wariber [46]1 year ago
5 0

[CO(en)₃]³⁺   is more stable than [CO(CH₃NH₂)]³⁺ to make more stable complex because of chelate effect.

[CO(en)₃]³⁺  is a metal chelate due to presece of bidentate ligand ethylene diamine ligand. Metal chelates are more stable than complexes containing only monodentate ligands because of the chelate effect, we expect ethylenediamine to form a stronger complex with Co than ammonia.

The Chelate Effect is that complexes resulting from coordination with the chelating ligand is much more thermodynamically stable than complexes with non-chelating ligands.

The chelate effect defined as  the augmented affinity of chelating ligands for any metalic ion in comparison of the affinity of a similar nonchelating ligands for the same metallic ion.

learn more about chelate effect at brainly.com/question/15242975

#SPJ4

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The structure is given in attached file.

Explanation:

Explanation

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3 years ago
A very simple assumption for the specific heat of a crystalline solid is that each vibrational mode of the solid acts independen
MatroZZZ [7]

Answer:

4.7 kJ/kmol-K

Explanation:

Using the Debye model the specific heat capacity in kJ/kmol-K

c = 12π⁴Nk(T/θ)³/5

where N = avogadro's number = 6.02 × 10²³ mol⁻¹, k = 1.38 × 10⁻²³ JK⁻¹, T = room temperature = 298 K and θ = Debye temperature = 2219 K  

Substituting these values into c we have

c = 12π⁴Nk(T/θ)³/5  

= 12π⁴(6.02 × 10²³ mol⁻¹)(1.38 × 10⁻²³ JK⁻¹)(298 K/2219 K)³/5

= 9710.83(298 K/2219 K)³/5

= 1942.17(0.1343)³

= 4.704 J/mol-K

= 4.704 × 10⁻³ kJ/10⁻³ kmol-K

= 4.704 kJ/kmol-K

≅ 4.7 kJ/kmol-K

So, the specific heat of diamond in kJ/kmol-K is 4.7 kJ/kmol-K

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