Answer:
The probability 
Step-by-step explanation:
From the question we are told that
The population proportion is p = 0.90
The sample size is n = 30
Generally mean of the sampling distribution is 
Generally the standard deviation is mathematically represented as

=> 
=> 
Generally the he probability that the proportion surviving for at least five years will exceed 80%, rounded to 5 decimal places is mathematically represented as

Generally 
So

From the z-table 
So

Answer:
i don't know. it doesn't depend my major. so hard for me
Given:
The right triangular prism.
Height of prism = 28 in.
Hypotenuse of base = 25 in.
leg of base = 24 in.
To find:
The lateral surface area of the prism.
Solution:
Pythagoras theorem:

Using Pythagoras theorem in the base triangle, we get




The perimeter of the triangular base is:


Lateral area of a triangular prism is:

Where, P is the perimeter of the triangular base and h is the height of the prism.
Putting
in the above formula, we get


Therefore, the lateral area of the prism is 1568 in².