What is the unit rate of 6 2/5 revolutions in 2 2/3 seconds

2 answers:

7 0

1) Convert mixed fractions into fractions.

6 2/5 = ((6*5) + 2) / 5 = 32 / 5
2 2/3 = ((2*3) + 2) / 3 = 8 / 3

2) 32 / 5 ÷ 8 / 3 ; where 32/5 is the 1st fraction and 8/3 is the 2nd fraction
a) Get the reciprocal of the 2nd fraction:
From 8/3 to 3/8
b) Multiply 1st fraction to the reciprocal of the 2nd fraction
32 / 5 * 3 / 8 = (32*3) / (5*8) = 96 / 40
c) Simplify the fraction.
96 / 40 divide by 4 will become 24/10.
24 / 10 divide by 2 will become 12 / 5. The simplified fraction of 96/40.

The unit rate is 12 / 5 = 2 2/5 revolutions per second.

DerKrebs [107]3 years ago

7 0

If you would like to know what is the unit rate, you can calculate this using the following steps:

6 2/5 revolutions ... 2 2/3 seconds
x revolutions = ? ... 1 second

6 2/5 * 1 = 2 2/3 * x
32/5 = 8/3 * x /*3/8
x = 32/5 * 3/8
x = 12/5
x = 2 2/5 revolutions

The correct result would be 2 2/5 revolutions per second.

You might be interested in

What is the domain of the square root function graphed below?

erma4kov [3.2K]

Answer:

The domain of the graph must be $x\ge \:-4$ .

Therefore,

$x\ge \:-4\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\ge \:-4\:\\ \:\mathrm{Interval\:Notation:}&\:[-4,\:\infty \:)\end{bmatrix}$

Hence, option a is true.

Step-by-step explanation:

From the graph, it is clear that the graph is heading towards positive infinity from x=-4.

The point x=-4 is included in the graph as the starting point of the graph i.e. x=4 is showing a closed circle on x=4, and heading towards positive infinity onward.

i.e. [-4, ∞)

Hence, the domain of the graph must be $x\ge \:-4$ .

Therefore,

$x\ge \:-4\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\ge \:-4\:\\ \:\mathrm{Interval\:Notation:}&\:[-4,\:\infty \:)\end{bmatrix}$

Hence, option a is true.

3 0

3 years ago

57000 x45 pls helppppppp

Varvara68 [4.7K]

Answer:

2565000

Step-by-step explanation: