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3 years ago

How can a driver best be prepare to enter sharp curves

Physics

1 answer:

Eduardwww [97]3 years ago

7 0

Slow down before entering the curve. Stay close to the outside. Use the gas pedal as you enter the middle of the curve.

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Each plate of a parallel‑plate capacitor is a square of side 4.19 cm, 4.19 cm, and the plates are separated by 0.407 mm. 0.407 m

alexandr1967 [171]

Answer:

The electric field strength inside the capacitor is 49880.77 N/C.

Explanation:

Given:

Side length of the capacitor plate (a) = 4.19 cm = 0.0419 m

Separation between the plates (d) = 0.407 mm = $0.407\times 10^{-3}\ m$

Energy stored in the capacitor (U) = $7.87\ nJ=7.87\times 10^{-9}\ J$

Assuming the medium to be air.

So, permittivity of space (ε) = $8.854\times 10^{-12}\ F/m$

Area of the square plates is given as:

$A=a^2=(0.0419\ m)^2=1.75561\times 10^{-3}\ m^2$

Capacitance of the capacitor is given as:

$C=\dfrac{\epsilon A}{d}\\\\C=\frac{8.854\times 10^{-12}\ F/m\times 1.75561\times 10^{-3}\ m^2 }{0.407\times 10^{-3}\ m}\\\\C=3.819\times 10^{-11}\ F$

Now, we know that, the energy stored in a parallel plate capacitor is given as:

$U=\frac{CE^2d^2}{2}$

Rewriting in terms of 'E', we get:

$E=\sqrt{\frac{2U}{Cd^2}}$

Now, plug in the given values and solve for 'E'. This gives,

$E=\sqrt{\frac{2\times 7.87\times 10^{-9}\ J}{3.819\times 10^{-11}\ F\times (0.407\times 10^{-3})^2\ m^2}}\\\\E=49880.77\ N/C$

Therefore, the electric field strength inside the capacitor is 49880.77 N/C

8 0

3 years ago

Type of force that holds the nucleus of an atom together

Kamila [148]

Answer:

Nuclear Forces

Explanation:

The type of force that holds the nucleus of an atom together is called Nuclear Forces.

7 0

3 years ago

Evaluate the use of hydrogen as a fuel. Explain how hydrogen is produced. Write about the environmental impact of using diesel a

nadya68 [22]

Explanation:

hydrogen is primarily produce by steam reforming of natural gas... Methane reacts with steam under 3 -25 bar pressure in the presence of a catalyst to "Produce Hydrogen " , carbon monoxide, and the greenhouse gas carbon dioxide. For steam to proceed, heat must be supplied to the process. Furthermore , new research from Transport & Environment shows that diesel cars not only pollute the air but also emit more climate change emissions (co2) than petroleum gas cars whenever compared to diesel fueled vehicles lifetime. In fact, diesel engines emits 3.65 tonnes of co2 more than a petrol engine equivalent.

6 0

3 years ago

Radioactive plutonium−239 (t1/2 = 2.44 × 105 yr) is used in nuclear reactors and atomic bombs. If there are 3.50 × 102 g of the

madam [21]

Answer:

t = 4.41 10⁻⁴ years

Explanation:

For this exercise we must use the concept of average life time, which is the time in which the quantity and substance decays in half

$T_{1/2}$ = ln2 / λ

Let's calculate the decay constant of plutonium

λ = ln2 / $T_{1/2}$

λ = ln 2 / 2.44 10⁵

λ = 2.84 10⁻⁶ s⁻¹

Radioactive decay is a first order process

N = No e (-λ t)

Where N is the number of nuclei, the mass is this by molecular weight

m = N PM

m / PM = m₀ / PM e (- λ t)

m / m₀ = e (- λ t)

-λ t = ln (m / m₀)

t = -1 /λ ln (m/m₀)

t = - 1 / 2.84 10⁻⁶ ln (0.1 / 0.35)

t = 4.41 10⁻⁴ years

7 0

3 years ago

Two flat 4.0 cm × 4.0 cm electrodes carrying equal but opposite charges are spaced 2.0 mm apart with their midpoints opposite ea

serious [3.7K]

Answer:

1.77 x 10^-8 C

Explanation:

Let the surface charge density of each of the plate is σ.

A = 4 x 4 = 16 cm^2 = 16 x 10^-4 m^2

d = 2 mm

E = 2.5 x 10^6 N/C

ε0 = 8.85 × 10-12 C2/N ∙ m2

Electric filed between the plates (two oppositively charged)

E = σ / ε0

σ = ε0 x E

σ = 8.85 x 10^-12 x 2.5 x 10^6 = 22.125 x 10^-6 C/m^2

The surface charge density of each plate is ± σ / 2

So, the surface charge density on each = ± 22.125 x 10^-6 / 2

= ± 11.0625 x 10^-6 C/m^2

Charge on each plate = Surface charge density on each plate x area of each plate

Charge on each plate = ± 11.0625 x 10^-6 x 16 x 10^-4 = ± 1.77 x 10^-8 C

7 0

3 years ago