Answer:
The right solution is "126 Psi".
Explanation:
The given values are:
P₁ = 130 psig
i.e.,
= 
= 
or,
= 
Z₂ = 10ft
= 3.05 m
= 1000 kg/m³
According to the question,
Z₁ = 0
V₁ = V₂
As we know,
⇒ 
On substituting the values, we get
⇒ 
⇒ 
⇒ 
i.e.,
⇒ 
⇒ 
I would think 10 but I would have to see the picture
<h2>Energy remains constant </h2>
Explanation:
Thermodynamic Laws -
- The primary law, otherwise called the Law of Conservation of Energy, expresses that energy remains constant in the overall reaction, it is not created or destroyed.
- The second law of thermodynamics expresses that the entropy increases. after the completion of the reaction of any isolated system
- The third law of thermodynamics expresses that as the temperature reaches towards an absolute zero point the entropy of a system becomes constant.
Standard Electronic potential -
- The standard reduction potential may be defined as the tendency of a chemical species or the reactants to get into its reduced form after the overall reaction.
- It is estimated at volts.
- The more is the positive potential the more is the reduction of the chemical species
Aerobic grow is much more efficient at making ATP because of the presence of oxygen the cycles in the respiration are carried out at an efficient rate which forces the cell to undergo a much large amount of ATP production.
Answer:
aluminium > copper > steel (amount which get sag)
Explanation:
<u>Theory</u>
Linear expansivity (α) : The increase in length, per unit length per degree rise in temperature.
Therefore, α = Δl/Lθ
Δl = increase in length ( amount of sag in this case )
L = length of wire
θ = temperature change
We get, Δl = Lαθ
From that we get, amount of sag ∝ Linear expansivity (α)
Initial length of all three wires are the same.
The temperature change they subject also the same.
So the factor that changes the amount of sag is the coefficient of linear expansivity.
Answer:

The Required horizontal force is 230.04N
Explanation:
Since the velocity is constant so acceleration is zero; a=0
Now the horizontal force required to move the pickup is equal to the frictional force.

where:
F_{Hn} is the required Force
u is the friction coefficient
m is the mass
g is gravitational acceleration=9.8m/s^2
Eq (1)
Now, weight increases by 42% and friction coefficient decreases by 19%
New weight=(1.42*m*g) and new friction coefficient=0.81u
Eq (2)
Divide Eq(2) and Eq (1)

The Required horizontal force is 230.04N