If the car travels
300 km.........................5 hrs
?km ..............................2h
to find out we do (300*2)/5=600/5=120km
also
300km/5h=60km/h
in 2 hours
120km
Answer:
No. Neither the USGS nor any other scientists have ever predicted a major earthquake. We do not know how, and we do not expect to know how any time in the foreseeable future.
7. 1.47 x 10^5mm to kilometers
Answer: 0.147
Shown answer:
8.4.7 kg to pounds
Answer:
Shown answer:
9.138.4oz to grams
Answer: 3923.574
Shown Answer:
10. 65.5km to miles
Answer: 40.69981
Shown answer:
11. 23.6ft to cm
Answer: 719.328
Shown answer:
12. 2.36 x 10^4 s to days
Answer: 0.273148148 days
Shown answer:
13. 13.6 L to U.S. Liquid quarts
Answer:
Shown answer:
show the work
help me and ill help you?
Answer:
Explanation:
Let's analyze the situation presented in order to know which answer is correct.
When the stick collides with the puck, it exerts a force for a certain time and discants. / After this time the horizontal force decreases to zero and the disk continues to move by the action of the initial velocity on the x axis and the acceleration of gravity on the y axis.
Therefore, after the collision, the only force that acts on the disk is the gravitational attractive force (WEIGHT), directed on the axis and in a negative direction.
The correct answer is:
C) Since there is no frictional force exerted on the puck, a normal force is not exerted on the puck, but the gravitational force is exerted on the puck
Answer:
v = 16.11 m / s
Explanation:
For this exercise we must use the principle of conservation of energy. We set a reference system on the part of the platform without elongation
starting point. When the spring is compressed
Em₀ = K_e + U = ½ k x² + m g x ’
final point. The point where it leaves the platform
Em_f = K = ½ m v²
energy is conserved
Em₀ = Em_f
½ k x² + m g x ’= ½ m v²
v² = 
x² + g x
let's calculate
v² = 
1.25² + 9.8 1.25
v² = 247.159 + 12.25 = 259.409
v = 16.11 m / s
