There are 67.2 liters of CO2 at STP
<h3>Further explanation</h3>
Given
3 mole of CO2
Required
Volume of CO2 at STP
Solution
Standard conditions for temperature and pressure are used as a reference in certain calculations or conditions
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.
So for 3 moles :
= 3 x 22.4 L
= 67.2 L
<em>The frequency of the wave with a wavelength of is</em> <u>3.748 × 10 ⁶ /s</u>.
I attached the working and the answer to the question below. I hope I was able to help.
Please note that C = speed of light (2.998 × 10⁸ m/s), ν = frequency and λ= wavelength.
You are given
200 grams of H2O(s) at an initial temperature of 0°C. you are also given the
final temperature of water after heating at 65°C. You are required to get the
total amount of heat to melt the sample. The specific heat capacity, cp, of
water is 4.186 J/g-°C. Let us say that T1 = 0°C and T2 = 65°C. The equation for
heat, Q, is
Q = m(cp)(T2-T1)
Q = 200g(4.186
J/g-°C )(65°C - 0°C)
<u>Q =
54,418J</u>
Answer:
Second option. 3
Explanation:
In order to balance a equation you need to have the same amount of atoms/moles in both sides.
Na₃PO₄ + _ HCl → 3NaCl + H₃PO₄
In reactant side we have 3 Na and we have the same amount in product side.
We also have 1 P and 4 O in both sides of the equation.
As we have 3 moles of NaCl in product side, this means we have:
NaCl → Na⁺ + Cl⁻
3 moles of Na⁺ and 3 moles of Cl⁻. In conclussion we need 3 moles of Cl⁻ in reactant side.Then, the stoichiometry of HCl must be, 3.
3 moles of HCl means that we have 3 moles of protons (H⁺).
HCl → H⁺ + Cl⁻
If you see the phosphoric acid, we also have 3 moles of protons.
H₃PO₄ → 3H⁺ + PO₄³⁻
Complete balanced equation is:
Na₃PO₄ + 3HCl → 3NaCl + H₃PO₄
Answer:
0.7556 mol
Explanation:
each mole has 6.022 X 10²³ particles (our particles are molecules in this situation)
(4.55 X 10²³)/(6.022 X 10²³) = 4.55/6.022 = 0.7556
