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andrew11 [14]
3 years ago
5

PLEASE HELP ME!! Show all work. Must be in standard form. Simplify (3x^2+4x-7)-9x^2-x+3)

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
7 0
I think this is the answer

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Marcos has 3/5 of a pizza remaining and gives his friend 1/5 of the remaining pizza. How much pizza is left over?
LuckyWell [14K]

Answer

at first I said 1/2 but it's 2/5's.

Step-by-step explanation:

\frac{3}{5}  -  \frac{1}{5 }  =  \frac{2}{5}

3 0
3 years ago
Suppose it is known that 60% of radio listeners at a particular college are smokers. A sample of 500 students from the college i
vladimir1956 [14]

Answer:

The probability that at least 280 of these students are smokers is 0.9664.

Step-by-step explanation:

Let the random variable <em>X</em> be defined as the number of students at a particular college who are smokers

The random variable <em>X</em> follows a Binomial distribution with parameters n = 500 and p = 0.60.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

1. np ≥ 10

2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=500\times 0.60=300>10\\n(1-p)=500\times(1-0.60)=200>10

Thus, a Normal approximation to binomial can be applied.

So,  

X\sim N(\mu=600, \sigma=\sqrt{120})

Compute the probability that at least 280 of these students are smokers as follows:

Apply continuity correction:

P (X ≥ 280) = P (X > 280 + 0.50)

                   = P (X > 280.50)

                   =P(\frac{X-\mu}{\sigma}>\frac{280-300}{\sqrt{120}}\\=P(Z>-1.83)\\=P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that at least 280 of these students are smokers is 0.9664.

8 0
3 years ago
Sripathi 10 years old than ragu. their total age is 100
Fiesta28 [93]
S = 10 + r

s + r = 100

Adding equations,

2s +r = 110 + r

2s = 110

s = 55

r = 45


8 0
3 years ago
What's substitution for:<br> X=y-7<br> X+8y=2
MrRissso [65]
\left \{ {{x=y-7} \atop {x+8y=2}} \right. \\\\&#10;substitute\ x=y-7\ into \ the\ second\ equation\\\\&#10;y-7+8y=2\\\\&#10;9y-7=2\ \ \ | add\ 7\\\\&#10;9y=9\ \ \ | divide\ by\ 9\\\\&#10;y=1\\\\x=y-7=1-7=-6
4 0
3 years ago
Given the following functions, evaluate f×g(7)
lidiya [134]

0

evaluate g(7) by substituting x = 7 into g(x

g(7) = (49-35-10)/2 = 4/2 = 2

now substitute x = 2 into f(x)

f(2) = √(4 - 48 + 144) = √0 = 0

(f ○ g)(7) = 0


3 0
3 years ago
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