Answer:
bad in this..............
Answer:
a) 13 m/s
b) (15 + h) m/s
c) 15 m/s
Step-by-step explanation:
if the location is
y=x²+3*x
then the average velocity from 3 to 7 is
Δy/Δx=[y(7)-y(3)]/(7-3)=[7²+3*7- (3²+3*3)]/4= 13 m/s
then the average velocity from x=6 to to x=6+h
Δy/Δx=[y(6+h)-y(6)]/(6+h-6)=[(6+h)²+3*(6+h)- (6²+3*6)]/h= (2*6*h+3*h+h²)/h=2*6+3= (15 + h) m/s
the instantaneous velocity can be found taking the limit of Δy/Δx when h→0. Then
when h→0 , limit Δy/Δx= (15 + h) m/s = 15 m/s
then v= 15 m/s
also can be found taking the derivative of y in x=6
v=dy/dx=2*x+3
for x=6
v=dy/dx=2*6+3 = 12+3=15 m/s
I believe the answers are c and d
X=200
2/3 of 15 is 10 make that negative add it to the other side 1/5x = 40 and then multiply 40 by 5 to get your answer
Check
1/5 of 200 is 40 - 10 = 30
40-10=30
30=30
Answer:
a=9.641, b=11.49
Vector will be 9.641 i + 11.49 j
Step-by-step explanation:
We have given that vector V has the magnitude of 15
And it makes an angle of 50
with positive x axis
Now let the x component of vector V is a and y component of vector V is b
So 
In vector form 9.641 i+11.49 j
