Answer:

Explanation:
Hello there!
In this case, considering the Avogadro's gas law, which treats the volume and moles in a directly proportional way via:

Which can be solved for the final volume, V2, as shown below:

Thus, by plugging in the given data, we obtain:

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Answer:
43.93 g/mol
Explanation:
The mass of the gas before reaction = 52.1487 g
The mass of the gas after reaction = 52.1098 g
Mass of gas generated = 0.0389 g
Moles of the gas = 
The formula for the calculation of moles is shown below:

Thus,


Molar mass of the gas = 43.93 g/mol
Bromine. both Bromine and Mercury are both a liquid at STP. :)
Answer:
It is present in the second group of the periodic table
Explanation: