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2 years ago

How many grams of oxygen are needed to react with 56.8 grams of ammonia?

Chemistry

1 answer:

Olin [163]2 years ago

3 0

The amount of oxygen needed would be 80.19 grams

<h3>Stoichiometric problems</h3>

From the equation of the reaction:

$4NH_3 +3 O_2 --- > 2N_2 + 6H_2O$

The mole ratio of oxygen and ammonia is 3:4

Mole of 56.8g ammonia = 56.8/17 = 3.34 moles

Equivalent mole of oxygen = 3/4 x 3.34 = 2.5059 moles

Mass of 2.5059 moles oxygen = 2.5059 x 32 = 80.19 grams

More on stoichiometric problems can be found here: brainly.com/question/15047541

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An element has two naturally-occurring isotopes. The mass numbers of these isotopes are 113 amu and 115 amu, with natural abunda

DENIUS [597]

Answer: Its average atomic mass is 114.9 amu

Explanation:

Mass of isotope 1 = 113 amu

% abundance of isotope 1 = 5% = $\frac{5}{100}=0.05$

Mass of isotope 2 = 115 amu

% abundance of isotope 2 = 95% = $\frac{95}{100}=0.95$

Formula used for average atomic mass of an element :

$\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})$

$A=\sum[(113\times 0.05)+(115\times 0.95)]$

$A=114.9amu$

Thus its average atomic mass is 114.9 amu

5 0

3 years ago

What causes the formation of mountain ranges along the ocean floor?

svp [43]

I think it is plate tectonics pulls the ocean floor apart and magma pushes up forming mountains, please tell me if i’m wrong but i hope this helps

4 0

3 years ago

Read 2 more answers

Magnalium alloys contain 70% Al and 30.0% Mg by mass. How many grams of H2(g) are produced in the reaction of a 0.710g sample of

Elis [28]

Answer:

H2 produced = 0.4235g

Explanation:

Equations for reaction with Hcl

Aluminium

2Al + 6 Hcl ------------ 2Alcl3 + 3H2

Magnesium

Mg + 2Hcl -------- Mgcl2 + H2

Aluminium = 70% of 0.710g of sample

sample contains (70 x 0.710)/100 = 0.497g of aluminium

Magnesium = 30% of 0.710g of sample

sample contains(30 x 0.710)/100 = 0 .213g of magnesium

Moles = mass/ molecular mass

Moles of aluminium in sample = 0.497/27 = 0.0184

2 moles of aluminium gives 3 moles of H2

No of moles of H2 from reaction with aluminium = (2 x0.0184)/3

= 0.0123 moles

1 mole of H2 = 2g therefore mass of H2 produced = 0.0123 x 2 = 0.0246g

Moles of magnesium in sample = 0.213/24 = 0.008875

1 mole of mg gives 1 mole of H2

No of moles of H2 from reaction with magnesium = 0.008875 x 1

= 0.008875

1 mole of H2 = 2g therefore mass of H2 produced = 0.008875 x 2

= 0.01775g

Ttal mass of H2 = 0.0246 +0.01775 = 0,04235g

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3 years ago

What is the number of sub shells in the 3rd main shell?

valkas [14]

The answer would be 2

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3 years ago

What happens with valence electrons to form a chemical bond?

dybincka [34]

Answer:

A valence electron is an outer shell electron that is associated with an atom, and that can participate in the formation of a chemical bond. If the outer shell is not closed; in a single covalent bond. Both atoms in the bond contribute one valence electron in order to form a shared pair.

(Hope this helps) Sky

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4 years ago