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2 years ago

How many grams of oxygen are needed to react with 56.8 grams of ammonia?

Chemistry

1 answer:

Olin [163]2 years ago

3 0

The amount of oxygen needed would be 80.19 grams

<h3>Stoichiometric problems</h3>

From the equation of the reaction:

$4NH_3 +3 O_2 --- > 2N_2 + 6H_2O$

The mole ratio of oxygen and ammonia is 3:4

Mole of 56.8g ammonia = 56.8/17 = 3.34 moles

Equivalent mole of oxygen = 3/4 x 3.34 = 2.5059 moles

Mass of 2.5059 moles oxygen = 2.5059 x 32 = 80.19 grams

More on stoichiometric problems can be found here: brainly.com/question/15047541

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Answer:

The molality of solution=12.605 m

Explanation:

We are given that

Molar mass of Hydrogen peroxide, M=34 g/mol

Density of solution, $\rho=1.11gcm^{-3}$

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Total mass of solution, m=100 g

Number of moles of solute= $\frac{given\;mass}{molar\;mass}$

Using the formula

Number of moles of hydrogen peroxide= $\frac{30}{34}$

Now, molality of solution

$m=\frac{number\;of\;moles\;of\;solute}{mass\;of\;solvent}\times 1000$

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Hence, the molality of solution=12.605 m

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3 years ago

When dissolving gases in water, the amount dissolving (decreases, does not change, increases) when the pressure is increased?

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4 years ago

How can you identify a chloride from an iodide solution using the silver nitrate and sodium thiosulfate test?

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How many moles are in 5.72 grams of iron (II) chloride

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Answer:

0.0451 mol FeCl₂

General Formulas and Concepts:

Chemistry - Atomic Structure

Reading a Periodic Table
Using Dimensional Analysis

Explanation:

Step 1: Define

5.72 g FeCl₂

Step 2: Identify Conversions

Molar Mass of Fe - 55.85 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of FeCl₂ - 55.85 + 2(35.45) = 126.75 g/mol

Step 3: Convert

$5.72 \ g \ FeCl_2(\frac{1 \ mol \ FeCl_2 }{126.75 \ g \ FeCl_2} )$ = 0.045128 mol FeCl₂

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

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