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vodomira [7]
2 years ago
10

Help ASAP I will mark brainliest for the correct answer !!!⚡️⚡️⚡️

Chemistry
2 answers:
kobusy [5.1K]2 years ago
8 0
Which fractions are equivalent to 0.875?
Tcecarenko [31]2 years ago
5 0

Answer:

A) 0.5h

Explanation:

Using the formula,

speed=\frac{distance}{time}

Substituting given values

1224=612/time

time=0.5h

You might be interested in
9. How do airbags protect the occupants of a car in a crash? Use the following words in
pentagon [3]
\textbf{Answer:}

Airbags are good for car crashes and have saved lots of life’s, the force of the airbags are dangerous though because they come out with fast acceleration and when it is hot it can burn you. If there is ever a time for collision airbags may save your live!

- ( I would appreciate if you gave brainliest if I helped you, if not please let me know what I got wrong! If you need any more help do not hesitate to ask! :) )

5 0
2 years ago
The client's lab values are sodium 166 mEq/L, potassium 5.0 mEq/L, chloride 115 mEq/L, and bicarbonate 35 mEq/L. What condition
Fantom [35]

Answer:

The anion value of 21mEq/L suggest the client will have metabolic acidosis

Explanation:

Anion gap is the interval or difference between measured cations (Sodium and Potassium) with the sum of measured anions (chloride and bicarbonate)

Using the above mentioned data

(166 + 5) - (115 + 35)  =  21mEq/L

Therefore the Anion gap = 21mEq/L

5 0
3 years ago
PLEASE HELP!!!!!!!!!! DOING A TEST
Nastasia [14]
D is the correct answer
4 0
3 years ago
Read 2 more answers
Materials expand when heated. Consider a metal rod of length L0 at temperature T0. If the temperature is changed by an amount ΔT
marysya [2.9K]

Answer:

(a) The length at temperature 180°C is 40.070 cm

(b) The length at temperature 90°C is 64.976 inches

(c) L(T, α) = 60·α·T - 9000·α + 60

Explanation:

(a) The given parameters are

The thermal expansion coefficient, α for steel = 1.24 × 10⁻⁵/°C

The initial length of the steel L₀ = 40 cm

The initial temperature, t₀ = 40°C

The length at temperature 180°C = L

Therefore, from the given relation, for change in length, ΔL, we have;

ΔL = α × L₀ × ΔT

The amount the temperature changed ΔT = 180°C - 40°C = 140°C

Therefore, the change in length, ΔL, is found as follows;

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 40 × 140°C = 0.07 cm

Therefore, L =  L₀ + ΔL = 40 + 0.07 = 40.07 cm

The length at temperature 180°C = 40.07 cm

(b) Given that the length at T = 120°C is 65 in., we have;

The temperature at which the new length is sought = 90°C

The amount the temperature changed ΔT = 90°C - 120°C = -30°C

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 65 × -30°C = -0.024375 inches

The length, L at 90°C is therefore, L = L₀ + ΔL = 65 - 0.024375 = 64.976 in.

The length at temperature 90°C = 64.976 inches

(c) L = L₀ + ΔL  = L₀ +  α × L₀ × ΔT = L₀ +  α × L₀ × (T - T₀)

Therefore;

L = 60 +  α × 60 × (T - 150°C)

L = 60 + α × 60 × T - 9000 × α

L(T, α) = 60·α·T - 9000·α + 60

7 0
3 years ago
Help pls!!!!!!!!!!!!!​
UkoKoshka [18]

Answer:

1.   C + O₂ → CO₂

2.  C + CO₂ → 2 CO

3. Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂

4 0
2 years ago
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