Answer:
80.1 grams
Explanation:
Find the molar mass of CH3OH first by using the periodic table values.
12.011 g/mol C + (1.008*3 g/mol H) + 15.999g/mol O + 1.008 g/mol H
=32.042 so that is the molar mass
Now that you have 2.50 moles of CH3OH, you can calculate the mass in g
2.50molCH3OH * (32.042g CH3OH / 1 mol CH3OH) = 80.105
32.042g / 1 mol is the same as 32.042 g/mol
Since there are 3 sig figs in the problem (2.50 has 3 sig figs), you round to 80.1 g CH3OH
<span>took two ethanoic acid molecules and removed a molecule of water between them you would get the acid anhydride, ethanoic anhydride. The old name: acetic anhydride.</span>
Answer:
Environment: They must be supplied and used in ways that have minimal safety and environmental stewardship have advanced safety regulations and practices, promulgated rules for reducing VOC emissions from oil and gas production and ... disposal protocols are similarly reducing negative impacts to air and water.
Explanation:
balance by putting 2 next to HF