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Ivanshal [37]
3 years ago
9

What is the [H3O+] in a solution with [OH-] = 1.0 x 10-12 M?

Chemistry
1 answer:
schepotkina [342]3 years ago
8 0

Answer:

The concentration of hydronium ions in the solution is 1.0\times 10^{-2}M.

Explanation:

Concentration of hydroxide ions concentration = [OH^-]=1.0\times 10^{-12} M

The pOH if the solution is given by :

pOH=-\log[OH^-]

pOH=-\log[1.0\times 10^{-12} M}]

pOH = 12

The relation between pH and OH is given by : pH + pOH = 14

pH = 14 - pOH

pH =14 - 12 = 2

The pH of the solution isgiven by :

pH=-\log[H_3O^+]

2=-\log[H_3O^+]

[H_3O^+]=1.0\times 10^{-2} M

The concentration of hydronium ions in the solution is 1.0\times 10^{-2}M.

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The distance between two consecutive crests and the length of a wave are the <em>wavelength</em>.

The distance between the highest and lowest points of a wave is <em>twice the amplitude</em>.

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Answer:

weak acid

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pH scale is from 0 to 14

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How much heat is absorbed when 447 g of water , Cp = 4.184 J/goC, goes from 25.0 oC to 35.0 oC?
Digiron [165]

Answer:

The answer to your question is  Q = 18702.5 J

Explanation:

Data

mass of water = m = 447 g

Cp = 4.184 J/g°C

Temperature 1 = T1 = 25°C

Temperature 2 = T2 = 35°C

Heat = Q = ? Joules

Process

1.- Write the formula to calculate heat

    Q = mCp(T2 - T1)

2.- Substitution

    Q = (447)(4.184)(35 - 25)

3.- Simplification

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4.- Result

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8 0
3 years ago
What is the theoretical yield of fluorenone if you oxidize 175 mg of fluorene?
My name is Ann [436]

Answer:

  • 602 mg of CO₂ and 94.8 mg of H₂O

Explanation:

The<em> yield</em> is measured by the amount of each product produced by the reaction.

The chemical formula of <em>fluorene</em> is C₁₃H₁₀, and its molar mass is 166.223 g/mol.

The <em>oxidation</em>, also know as combustion, of this hydrocarbon is represented by the following balanced chemical equation:

        2C_{13}H_{10}+31O_2\rightarrow 26CO_2+10H_2O

To calculate the yield follow these steps:

<u>1. Mole ratio</u>

          2molC_{13}H_{10}:31molO_2:26molCO_2:10molH_2O

<u />

<u>2. Convert 175mg of fluorene to number of moles</u>

  • 175mg/times 1g/1,000mg=0.175g

  • Number of moles = mass in grams / molar mass

  • \text{number of moles}=0.175g/166.223g/mol=0.0010528mol

<u>3. Set a proportion for each product of the reaction</u>

a) <u>For CO₂</u>

i) number of moles

         2molC_{10}H_{13}/26molCO_2=0.0010528molC_{10}H{13}/x

x=0.0010528molC_{10}H_{13}\times 26molCO_2/2molC_{10}H_{13}=0.013686molCO_2

ii) mass in grams

The molar mass of CO₂ is 44.01g/mol

  • mass = number of moles × molar mass
  • mass = 0.013686 moles × 44.01 g/mol = 0.602 g = 602mg

b) <u>For H₂O</u>

i) number of moles

0.0010528molC_{10}H_{13}\times10molH_2O/2molC_{10}H_{13}=0.00526molH_2O

ii) mass in grams

The molar mass of H₂O is 18.015g/mol

  • mass = number of moles × molar mass
  • mass = 0.00526 moles × 18.015 g/mol = 0.0948mg = 94.8 mg
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