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lilavasa [31]
2 years ago
13

A sugar crystal contains approximately 1.4×1017 sucrose (C12H22O11) molecules. What is its mass in milligrams? Express using 2 s

ig figs
Chemistry
2 answers:
alekssr [168]2 years ago
5 0

Answer:

From the periodic table:

mass of carbon = 12 grams

mass of hydrogen = 1 grams

mass of oxygen = 16 grams

molar mass of surcose = 12(12) + 22(1) + 11(16) = 342 grams

number of molecules = number of moles x Avogadro's number

number of moles = number of molecules / Avogadro's number

number of moles = (2.2x10^17) / (6.02x10^23) = 3.6544 x 10^-7 moles

number of moles = mass / molar mass

mass = number of moles x molar mass

= 1.7 x 10^17/6.022 x 10^23.

kodGreya [7K]2 years ago
4 0

Answer:

Our process would be just turning the molecules of sucrose to the moles by dividing using Avogadro's number (6.02 x 10^23), which will give us the moles we need. In order to find the mass of the sucrose, you have to multiply the moles by the molar mass of sucrose in order to find the mass, and then multiply by it 1000 to change it to mg.

Here are the formulas:

Number of moles = Number of molecules / Avogadro's number

Mass = Moles x Molar mass

Number of moles = (1.4 x 10^17) / (6.02 x 10^23) = <u>2.3255814 x 10^-7 </u>moles

Now that we have the moles, we can multiply them by Sucrose's molar mass, which can be calculated by using the masses listed in the periodic table.

Carbon's Molar Mass = 12g/mol (There are 12 atoms of Carbon in sucrose)

Hydrogen's Molar mass = 1.01g/mol (22 atoms of Hydrogen in sucrose)

Oxygen's Molar mass = 16g/mol (11 atoms of oxygen in sucrose)

Now we just add them together:

((12)x(12)) + ((1.01)x(22)) + ((16)x(11)) = <u>342.22g/mol</u> is the molar mass of Sucrose

Now back to the question, you multiply the moles of sucrose by its molar mass to get the mass in grams

(2.3255814 x 10^-7) x (342.22) = 0.0000796 grams

Now to get it in milligrams, you multiply the answer above by 1000

0.0000796 x 1000 = <u>0.079 mg (already in 2 sig figs)</u>

<u />

<u>Therefore there are 0.079 milligrams of sucrose in the sugar crystal.</u>

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Answer:

a) 0,2% w/v

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Explanation:

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b) Ratio strength is a way to express concentration.  For w/v is in 1g of solute <em>r</em> mililiters of solution have. Thus, r = 500 because we have in the first 1 g of CaCl₂ in 500 mL of solution.

c) Molarity is moles of solute per liter of solution, thus:

1,000 g of CaCl₂ × \frac{1mol}{110g} = 9,09×10⁻³ moles of CaCl₂

500 mL of solution  × \frac{1L}{1000mL} = 0,500 L of solution

M = \frac{9,09x10^{-3} moles }{0,500 L} = 0,0182 M

d) Molality is moles of solute per kg of solution.

Specific gravity is the ratio between density of the solution and density of a reference substance (Usually water). With a specific gravity of 0,8:

kg of solution = 0,500 L of solution × \frac{0,8 kg}{1L} =<em> </em><em>0,625 kg of solution</em>

m = \frac{9,09x10^{-3}moles }{0,625 kg} = 0,0145 m

e)  In a salt, equivalents are the number of moles ables to replace one mole of charge. In CaCl₂ is ¹/₂ because with  ¹/₂ moles of CaCl₂ it is possible to replace 1 mole of charges. Thus, in 1,5 L there are:

1,5 L ×\frac{0,0182 CaCl2 moles}{1L} × \frac{1equivalent}{2 moles} = 0,0137 equivalents

I hope it helps!

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