What is the atom number of an element that has six protons and eight neutrons?

The following two compounds are constitutional isomers. Identify which of these is expected to be more acidic, and explain your

Vladimir [108]

Answer:

c. Compound 2 is more acidic because its conjugate base is more resonance stabilized

Explanation:

You haven't told us what the compounds are, so let's assume that the formula of Compound 1 is HCOCH₂OH and that of Compound 2 is CH₃COOH.

The conjugate base of 2 is CH₃COO⁻. It has two important resonance contributors, and the negative charge is evenly distributed between the two oxygen atoms.

CH₃COOH + H₂O ⇌ CH₃COO⁻ + H₃O⁺

The stabilization of the conjugate base pulls the position of equilibrium to the right, so the compound is more acidic than 1.

6 0

3 years ago

What is the total anion concentration (in mEq/L ) of a solution that contains 6.0 mEq/L Na + , 11.0 mEq/L Ca 2+ , and 1.0 mEq/L

lubasha [3.4K]

24

Ddddd

Hope I helped

5 0

3 years ago

A 45-g aluminium spoon(specific heat 0.80 / J/gdegree Celsius) at 24 degree celsius is placed in 180 ml(180 grams) of coffee at

Vlad [161]

Explanation:

a) The amount of heat released by coffee will be absorbed by aluminium spoon.

Thus, $heat_{absorbed}=heat_{released}$

To calculate the amount of heat released or absorbed, we use the equation:

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

Also,

$m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]$ ..........(1)

where,

q = heat absorbed or released

$m_1$ = mass of aluminium = 45 g

$m_2$ = mass of coffee = 180 g

$T_{final}$ = final temperature = ?

$T_1$ = temperature of aluminium = $24^oC$

$T_2$ = temperature of coffee = $85^oC$

$c_1$ = specific heat of aluminium = $0.80J/g^oC$

$c_2$ = specific heat of coffee= $4.186 J/g^oC$

Putting all the values in equation 1, we get:

$45 g\times 0.80J/g^oC\times (T_{final}-24^oC)=-[180 g\times 4.186J/g^oC\times (T_{final}-83^oC)]$

$T_{final}=80.30^oC$

80.30 °C is the final temperature.

b) Energy flows from higher temperature to lower temperature.Whenever two bodies with different energies and temperature come in contact. And the resulting temperature of both bodies will less then the body with high temperature and will be more then the body with lower temperature.

So, is our final temperature of both aluminium and coffee that is 80°C less than initial temperature of coffee and more than the initial temperature of the aluminum.

8 0

2 years ago

Assuming the same temperature and pressure for each gas, how many milliliters of carbon dioxide are produced from 16.0 mL of CO?

Vlada [557]

Answer:

$V_{CO_2}=16.0mL$

Explanation:

Hello,

In this case, given that the same temperature and pressure is given for all the gases, we can notice that 16.0 mL are related with two moles of carbon monoxide by means of the Avogadro's law which allows us to understand the volume-moles relationship as a directly proportional relationship. In such a way, since in the chemical reaction:

$2CO(g)+O_2(g)\rightarrow 2CO_2(g)$

We notice two moles of carbon monoxide yield two moles of carbon dioxide, therefore we have the relationship:

$n_{CO}V_{CO}=n_{CO_2}V_{CO_2}$

Thus, solving for the yielded volume of carbon dioxide we obtain:

$V_{CO_2}=\frac{n_{CO}V_{CO}}{n_{CO_2}} =\frac{2mol*16.0mL}{2mol}\\ \\V_{CO_2}=16.0mL$

Best regards.

4 0

3 years ago

(a) What is the charge density of an ion, and what two properties of an ion affect it?

olga nikolaevna [1]

Charge density is the ratio of the charge of ions to the volume of ions.

<h3> Factor affecting charge density</h3>

It depends on the following properties of ion as

Charge on the ion.
Volume of the ions.

The lithium ion, Li⁺, has half of the radius of the potassium ion, K⁺. That is why, Li⁺ have a electric field 4 times stronger than the electric field of K⁺ and thus it have 4 times stronger force of attraction.

All the ions: Li⁺, Na⁺, K⁺, Rb⁺, Cs⁺, have the similar electric charge +1.6×10⁻¹⁹ C. As we know that, volume is directly proportional to the third power of their radius. Therefore, smaller ions have less charge density than bigger one.

We can say that charge density decreases down across period due to decrease in the radius which further reduces the volume of ions.

Charge density increases along group due to increase in the radius which further increases the volume of ions.

Thus, we can say that charge density depends on the charge and volume of the ions.

learn more about charge density:

brainly.com/question/15810178

#SPJ4

6 0

1 year ago