Answer:
20m
Step-by-step explanation:
Say you walk down the street for 10m. Then you take a left and walk for another 10m then go inside a bakery. You walked 10m on one street and 10m on another street to get to the bakery. In total you walked 20m to get to the bakery. We know this because 10 + 10 = 20.
I really do hope that this helps you! Have a blessed day!
B = (2x+3)(4x^2-6x+9)-2(4^3-1)
B = 8x^3-99
Hope it helps : )
Answer:
Option 3, p(0) = -10
Option 4, p(10) = 0
Step-by-step explanation:
<u>Step 1: Check</u>
x - 10 + 10 = 0 + 10
<em>x = 10</em>
f(0) = 0 - 10 = -10
x = -10
<em>p(10) = 0</em>
Answer: Option 3, p(0) = -10, Option 4, p(10) = 0
I think it’s A sorry if I’m wrong
Step-by-step explanation:
The solution to this problem is very much similar to your previous ones, already answered by Sqdancefan.
Given:
mean, mu = 3550 lbs (hope I read the first five correctly, and it's not a six)
standard deviation, sigma = 870 lbs
weights are normally distributed, and assume large samples.
Probability to be estimated between W1=2800 and W2=4500 lbs.
Solution:
We calculate Z-scores for each of the limits in order to estimate probabilities from tables.
For W1 (lower limit),
Z1=(W1-mu)/sigma = (2800 - 3550)/870 = -.862069
From tables, P(Z<Z1) = 0.194325
For W2 (upper limit):
Z2=(W2-mu)/sigma = (4500-3550)/879 = 1.091954
From tables, P(Z<Z2) = 0.862573
Therefore probability that weight is between W1 and W2 is
P( W1 < W < W2 )
= P(Z1 < Z < Z2)
= P(Z<Z2) - P(Z<Z1)
= 0.862573 - 0.194325
= 0.668248
= 0.67 (to the hundredth)
