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mars1129 [50]
3 years ago
9

A 300 kg buffalo runs across the prairie with a speed of 8 m/s. What is the kinetic energy of the Buffalo? A:19,200 j B:9600 j C

:4800 j D:1200 j
Physics
1 answer:
alina1380 [7]3 years ago
5 0
<h2>Answer: 9600 J</h2>

The kinetic energy K  of a body is that energy it possesses due to its movement and is defined as:

K=\frac{1}{2}mV^{2}

Where m is the mass of the body and V its velocity .

This has to do with the speed of an object and how much mass it has; basically how the object is moving.

Now, according to this equation and knowing that the mass of the buffalo is m=300kg  and its velocity V=8m/s :

K=\frac{1}{2}(300kg)(8m/s)^{2}

K=9600J

Therefore the correct option is B.

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6) Set the battery to a value between 0.0 V and 1.5 V. Now drag the voltage meter toward the capacitor and move the red and blac
KIM [24]

Answer:

A) 1.5 v

B) Top plate is at higher voltage than the bottom plate

Explanation:

Battery value set between 0.0 V and 1.5 V

a) The potential difference between the plates

Δ V = V1( potential at top plate) - V2( potential at lower plate )

potential at top plate = 1.5 V

potential at lower plate = 0.0 V

hence potential difference = 1.5 V

b ) The top plate is always connected to the positive terminal of the DC source ( which is at a higher potential )while the bottom plate is connected to the negative terminal of the DC source ( which is at a lower potential )

hence the Top plate is at higher voltage than the bottom plate

7 0
3 years ago
A karate master wants to break a board by hitting the board swiftly with his hand. The master's hand has a mass of 0.30 kg, and
slava [35]

Answer:

f=-1380N

Explanation:

A karate master wants to break a board by hitting the board swiftly with his hand. The master's hand has a mass of 0.30 kg, and as it strikes the board, his hand has a velocity of 23.3 m/s. The master contacts the board for 0.0050 seconds

.the concluding part to the question should be

What is the impact force (impulse) on the board?

solution

from the Newton's second law of motion which states that

the rate of change in momentum is directly proportional to the force applied

f=m(v-u)/t

f=0.3(0-23.3)/0.005

f=-1380N

f=force impact

m=mass of the karates master's hand

t=time for the impact

v=0m/s final velocity

u=initial velocity

6 0
4 years ago
Use the concepts on which maxwell’s equations are based to explain why a compass needle is deflected when the compass is brought
miv72 [106K]

A conductor that is conducting current generates a magnetic field everywhere around it. This magnetic field exerts force on the compass's magnetic needle, causing the needle to deviate.

Definition of Maxwell's rule

A current-conducting conductor creates a magnetic field everywhere around it. The magnetic needle of the compass experiences force from this magnetic field, which causes the needle to veer.

Equation for deflection

We have so far established that the total flux of electric field out of a closed surface is just the total enclosed charge multiplied by 1/ε0, ∫→E⋅d→A=q/ε0. This is Maxwell's first equation. It represents completely covering the surface with a large number of tiny patches having areas d→A.

To learn more about magnetic field refer : brainly.com/question/24761394

#SPJ4

7 0
2 years ago
What speed should a satellite with a mass of 1500 kg at 8,500 km above the center of the earth be traveling at in order to stay
hodyreva [135]

Answer:

6844.5 m/s.

Explanation:

To get the speed of the satellite, the centripetal force on it must be enough to change its direction. This therefore means that the centripetal force must be equal to the gravitational force.

Formula for centripetal force is;

F_c = mv²/r

Formula for gravitational force is:

F_g = GmM/r²

Thus;

mv²/r = GmM/r²

m is the mass of the satellite and M is mass of the earth.

Making v the subject, we have;

v = √(GM/r)

We are given;

G = 6.67 × 10^(-11) m/kg²

M = 5.97 × 10^(24) kg

r = 8500 km = 8500000

Thus;

v = √((6.67 × 10^(-11) × (5.97 × 10^(24)) /8500000) = 6844.5 m/s.

7 0
3 years ago
Read 2 more answers
To stop a car, first you require a certain reaction time to begin braking; then the car slows under the constant braking deceler
ANEK [815]

Answer:

a) t_r = 0.55 s

b) a = 5.59 m/s²

Explanation:

given,

total distance traveled by the car to stop is 56.9 m when speed of vehicle is 80 km/h or 80 × 0.278 = 22.24 m/s

total distance traveled by the car to stop is 25.7 m when speed of vehicle is 50.7 km/h or 50.7 × 0.278 = 14.09 m/s

using stopping distance formula

s_1 = v_1 t_r +\dfrac{v_1^2}{2 a}................(1)

s_2 = v_2 t_r +\dfrac{v_2^2}{2 a}..............(2)

on solving both the equation we get

a = \dfarc{v_1v_2(v_1-v_2)}{2(s_1v_2-s_2v_1)}

a = \dfarc{22.4\times 14.09(22.24-14.09)}{2(56.9\times 14.09-25.7\times 22.24)}

a = 5.59 m/s²

now reaction time calculation

t_r =\dfrac{v_1^2d_2-v_2^2d_1}{v_1v_2(v_1-v_2)}

t_r =\dfrac{22.24^2\times 25.7-14.09^2\times 56.9}{22.4\times 14.09(22.24-14.09)}

t_r = 0.55 s      

8 0
3 years ago
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