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77julia77 [94]
4 years ago
5

Suppose there are two transformers between your house and the high-voltage transmission line that distributes the power. In addi

tion, assume that your house is the only one using electric power. At a substation the primary coil of a step-down transformer (turns ratio = 1:29) receives the voltage from the high-voltage transmission line. Because of your usage, a current of 53.3 mA exists in the primary coil of this transformer. The secondary coil is connected to the primary of another step-down transformer (turns ratio = 1:32) somewhere near your house, perhaps up on a telephone pole. The secondary coil of this transformer delivers a 240-V emf to your house. How much power is your house using? Remember that the current and voltage given in this problem are rms values.
Physics
1 answer:
storchak [24]4 years ago
8 0

Answer:240-v

Explanation:

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Sonja [21]

Answer:

A current will not be induced.  

Explanation:  

The wire is not part of a closed circuit.

The electrical charges have no place to flow to.

6 0
3 years ago
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An unwary football player collides with a padded goalpost while running at a velocity of 7.50 m/s and comes to a full stop after
frez [133]

Answer:

(a) the deceleration of the player is -80.36 m/s²

(b) the time the collision last is 0.093 s

Explanation:

Given;

Initial velocity of the football player, u = 7.50 m/s

Final velocity of the football player, v = 0

distance traveled = compression of the pad, s = 0.35 m

Part (a) the deceleration of the player

v² = u² + 2as

0 = 7.5² + (2 x 0.35)a

0 = 56.25 + 0.7a

- 56.25 = 0.7a

a = -56.25 / 0.7

a = -80.36 m/s²

Part (b) the time the collision last

v = u + at

t = (v - u)/a

t = (0 - 7.5)/ -80.36

t = - 7.5 / -80.36

t = 0.093 s

7 0
3 years ago
Two positive charges are fixed a distance apart.the sun of their charges is Qt.what charge must each have in order to maximise t
romanna [79]

Answer:

Both charges must have the same charge, Qt/2.

Explanation:

Let the two charges have charge Q1 and Q2, respectively.

Use Coulombs's Law to find an expression for the force between the two charges.

F = k_e\frac{Q_1Q_2}{r^2}, where

Ke is Coulomb's contant and

r is the distance between the charges.

We know from the question that

Q1 + Q2 = Qt

So,

Q2 = Qt - Q1

F = k_e\frac{Q_1(Q_t - Q_1)}{r^2}

Simplify to obtain,

F = \frac{k_e}{r^2} (Q_tQ_1 - Q_1^2)

In order to find the value of Q1 for which F is the maximum, we will use the optimization technique of calculus.

Differentiate F with respect to Q1,

\frac{dF}{dQ_1}  = \frac{k_e}{r^2} (Q_t - 2Q_1)

Equate the differential to 0, to obtain the value of Q1 for which F is the maximum.

\frac{k_e}{r^2} (Q_t - 2Q_1) = 0\\Q_t - 2Q_1 = 0\\2Q_1 = Q_t\\Q1 = \frac{Q_t}{2}

It follows that

Q_2 = \frac{Q_t}{2}.

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