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4 years ago

8

Use the data table and compare your calculated predictions with the measured y positions. Record your results in the table below

. Describe any notable differences. Make a hypothesis about any differences.

1 answer:

-Dominant- [34]4 years ago

8 0

Answer:

0.3 s -0.4 m -0.57 m

0.5 s -1.2 m -1.27 m

0.7 s -2.3 m -2.4 m

Explanation:

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How fast, in meters per second, does an observer need to approach a stationary sound source in order to observe a 1.6 % increase

morpeh [17]

Answer:

The value is $v_o = 5.488 \ m/s$

Explanation:

From the question we are told that

The emitted frequency increased by $\Delta f = 1.6 \% = 0.016 \$

Let assume that the initial value of the emitted frequency is

$f = 100\% = 1$

Hence new frequency will be $f_n = 1 + 0.016 = 1.016$

Generally from Doppler shift equation we have that

$f_1 = [\frac{ v \pm v_o}{v \pm + v_s } ] f$

Here v is the speed of sound with value $v = 343 \ m/s$

$v_s$ is the velocity of the sound source which is $v_s = 0 \ m/s$ because it started from rest

$v_o$ is the observer velocity So

Generally given that the observer id moving towards the source, the Doppler frequency becomes

$f_1 = [\frac{ v + v_o}{v + 0 } ] f$

=> $1.016 = [\frac{ 343 + v_o}{343 } ] * 1$

=> $v_o = 5.488 \ m/s$

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3 years ago

What is the significant figure of 0.00000006

Maksim231197 [3]

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3 years ago

What does the w mean in w=fxd

Volgvan

Answer:

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Explanation:

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3 years ago

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Answer:

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Formula

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2 years ago