Answer:
Explanation:
cSep 20, 2010
well, since player b is obviously inadequate at athletics, it shows that player b is a woman, and because of this, she would not be able to hit the ball. The magnitude of the initial velocity would therefore be zero.
Anonymous
Sep 20, 2010
First you need to solve for time by using
d=(1/2)(a)(t^2)+(vi)t
1m=(1/2)(9.8)t^2 vertical initial velocity is 0m/s
t=.45 sec
Then you find the horizontal distance traveled by using
v=d/t
1.3m/s=d/.54sec
d=.585m
Then you need to find the time of player B by using
d=(1/2)(a)(t^2)+(vi)t
1.8m=(1/2)(9.8)(t^2) vertical initial velocity is 0
t=.61 sec
Finally to find player Bs initial horizontal velocity you use the horizontal equation
v=d/t
v=.585m/.61 sec
so v=.959m/s
Fperson =[( velocity of wind )+ or - (velocity of person)] / [(velocity of wind) + or - (velocity of sounds)] x frekuency of sounds
Answer:
it takes the car 4.362 seconds to cover the distance of 88.4 m.
Explanation:
The distance the car covers is given by the function
,
where 
, and 
, putting these in we get:
Now, when the car has moved to 88.4m, 
, or
which is a quadratic equation with solutions
We take the first solution 
, <em>since at that time the car is still moving right and decelerating</em>. The second solution 
describes the situation where the car has stopped decelerating and is now moving leftwards because the decelerating is leftwards, <em>which is utterly wrong because we know that cars do not start moving backwards after the brakes have stopped them! </em>
Thus, it takes the car 4.362 seconds to cover the distance of 88.4 m.
Answer:
<h2>Potential difference across capacitors in parallel
</h2>
Two or more capacitors are said to be connected in parallel if each one of them is connected across the same two points. In a parallel combination of capacitors potential difference across each capacitor is same but each capacitor will store different charge.
Answer:
A.) 355 m/s
B.) 0.71 m
C.) 500Hz
Explanation:
Given that a police car is traveling due east at a speed of 15.0 m/s relative to the earth. You are in a convertible following behind the police car. Your car is also moving due east at 15.0 m/s relative to the earth, so the speed of the police car relative to you is zero. The siren of the police car is emitting sound of frequency 500 Hz. The speed of sound in the still air is 340 m/s
a.) What is the speed of the sound waves relative to you?
Since the car is moving away from the observer, the relative velocity will be:
Relative velocity = 340 + 15
Relative velocity = 355 m/s
b.) What is the wavelength of the sound waves at your location?
Using the wave speed formula
V = frequency × wavelength
Make wavelength the subject of formula.
Wavelength = Velocity / frequency
Wavelength = 355/500
Wavelength = 0.71 m
c.) What frequency do you detect?
Fo = Fs ( C + V ) / ( C + v )
Fo = Fs
That is, the frequency of the observer will be equal to the frequency of the source.
Therefore, Fo = 500Hz
