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2 years ago

Johnny went to an apple farm to pick some apples. The admission to get in was $5.00 and the apples cost $0.75 per pound.

Mathematics

1 answer:

sasho [114]2 years ago

6 0

Answer:

y=0.75x+5

Step-by-step explanation:

It would be this equation because you start at 5, which is the y-intercept, then you add 0.75 for every pound of apples. So on a graph you would start at 5 on the y-line then go up by 0.75

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Ashton plays three games of checkers with his grandmother. Identify the

Marizza181 [45]

Answer:

Step-by-step explanation:

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2 years ago

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What is the sum of the answers to the eqation? <img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20-%206x%20%2B%205%2

MAVERICK [17]

Answer:

Step-by-step explanation:

$x^{2}$ - 6x +5 = 0

$x^{2}$ - 6x + 9 -9 +5 = 0

[ $x^{2}$ - 6x + 9] - 4 =0

$(x -3)^{2}$ -4 = 0

$(x -3)^{2}$ = 4

(x-3) = $\sqrt{4}$ or (x-3) = - $\sqrt{4}$

(x-3) = 2 or (x-3) = -2

x = 5 or x = 1

therefore, sum of these solutions is 5+1 = 6

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2 years ago

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Solve for x And show work

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Answer:

2x - 20 + 7 = x - 1

2x - 13 = x-1

2x = x+12

x = 12

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2 years ago

Determining whether two functions are inverses of each other.

murzikaleks [220]

F(x) = 6x + 5
g(x) = 6x - 5
f(g(x)) = 6(6x - 5) + 5 = 36x - 30 + 5 = 36x - 25
g(f(x)) = 6(6x+ 5) - 5 = 36x + 30 - 5 = 36x + 25

f and g are not inverse of each other.

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Suppose a random variable, x, arises from a binomial experiment. If n = 6, and p = 0.30, find the following probabilities using

AlladinOne [14]

Answer:

a) P(X=1) = 0.302526

b) P(X=5) = 0.010206

c) P(X=3) = 0.18522

d) P(X≤3) = 0.92953

e) P(X≥5) = 0.010935

f) P(X≤4) = 0.989065

Explanation:

Binomial experiments are modeled by the formula:

$P(X=x)=C(n,x)\cdot p^x\cdot (1-p)^{(n-x)}$

Where

P(X=x) is the probability of exactly x successes

$C(n,x)=\dfrac{n!}{x!\cdot (n-x)!}$

p is the probability of one success, which must be the same for every trial, and every trial must be independent of other trial.

n is the number of trials

1 - p is the probability of fail

there are only two possible outcomes for each trial: success or fail.

a.) P (x=1)

$P(X=1)=\dfrac{6!}{1!\cdot (6-1)!}\times (0.3)^1\times(1-0.3)^{(6-1)}=0.302526$

b.) P (x=5)

$P(X=5)=\dfrac{5!}{5!\cdot (6-5)!}\times (0.3)^5\times (1-0.3)^{(6-5)}=0.010206$

c.) P (x=3)

Using the same formula:

$P(X=3)=0.18522$

d.) P (x less than or equal to 3)

P(X≤3)= P(X=3) + P(X=2) + P(X=1) + P(X=0)

Also,

P(X≤3) = 1 - P(X≥4) = 1 - P(X=4) - P(X=5) - P(X=6)

You can use either of those approaches. The result is the same.

Using the second one:

P(X=4) = 0.059335
P(X=5) = 0.010206
P(X=6) = 0.000729

P(X≤3) = 1 - 0.05935 - 0.010206 - 0.000729 = 0.92953

e.) P(x greather than or equal to 5)

P(X≥5) = P(X=5) + P(X=6)

P(X≥5) = 0.010206 + 0.000729 = 0.010935

f.) P(x less than or equal 4)

P(X≤4) = 1 - P(X≥5) = 1 - P(X=5) - P(X=6)

P(X≤4) = 1 - 0.010206 - 0.000729 = 0.989065

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3 years ago