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galina1969 [7]
3 years ago
6

2. What is the sum of two numbers that are additive inverses?​

Mathematics
2 answers:
Stells [14]3 years ago
4 0

Answer:

what are the choices

Step-by-step explanation:

stich3 [128]3 years ago
3 0

So in other words, the additive inverse of x is another number, y, as long as the sum of x + y equals zero. The additive inverse of x is equal and opposite in sign to it (so, y = -x or vice versa). For example, the additive inverse of the positive number 5 is -5. That's because their sum, or 5 + (-5) = 0.

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Find the second derivative at the point (2,2), given the function below. 2x^4=4y^3
Bogdan [553]

The second derivative at the point (2,2) is 34/9

<u>Explanation:</u>

<u></u>

2x⁴ = 4y³

2x⁴ - 4y³ = 0

We first need to find dy/dx and then d²y/dx²

On differentiating the equation in terms of x

dy/dx = d(2x⁴ - 4y³) / dx

We get,

dy/dx = 2x³/3y²

On differentiating dy/dx we get,

d²y/dx² = 2x²/y² + 8x⁶/9y⁵

\frac{d^2y}{dx^2} = \frac{2 X 2^2}{2^2} + \frac{8 X 2^6}{9 X 2^5}\\  \\\frac{d^2y}{dx^2} = 2 + \frac{16}{9}\\  \\

d²y/dx² = 34/9

Therefore, the second derivative at the point (2,2) is 34/9

7 0
3 years ago
After solving an equation, you end up with integers on both sides of the equation. What can you interpret about the equation are
murzikaleks [220]

Answer:

The equation is:

An identity

Has infinitely many solutions

No solution

Step-by-step explanation:

Because there is integers on both sides, we know that any attempts to fix this will either cause an identity, or a false numerical equation(an identity but <em>w r o n g</em>).(Note, an identity can either mean 2 = 2 or x = x).

Identities have infinite solutions, because it does not matter what you put in, the equation will always be true. False equations do not have a solution because they aren't even true equations.

Hope this helps!

5 0
3 years ago
RSM wants to send four of its 18 Math Challenge teachers to a conference. How many combinations of four teachers include exactly
tatiyna

Answer:

1120 combinations of four teachers include exactly one of either Mrs. Vera or Mr. Jan.

Step-by-step explanation:

The order in which the teachers are chosen is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

1 from a set of 2(Either Mrs. Vera or Mr. Jan).

3 from a set of 18 - 2 = 16. So

C_{2,1}C_{16,3} = \frac{2!}{1!1!} \times \frac{16!}{3!13!} = 1120

1120 combinations of four teachers include exactly one of either Mrs. Vera or Mr. Jan.

4 0
3 years ago
I need help now btw i am in middle school
vodomira [7]

Answer: x= 3

Step-by-step explanation:

2x + 5 = 11

2x = 6

x = 3

5 0
3 years ago
Read 2 more answers
Find the average range. Round the mean and the average range to the nearest tenth. (Show all your work on scratch paper, then en
NISA [10]
3, 12, 15, 25, 30, 40The range is the difference between the greatest and smallest values:
range = 40 - 3 = 37

Thee average is the sum of elements divided by the number of elements:
average = (<span>3 + 12 + 15 + 25 + 30 + 40</span>)/6
average = 125/6 = 20.83
4 0
3 years ago
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