Answer:
78.5 mL
Explanation:
Step 1: Given data
Mass of the lead fishing weight: 39.7 g
Volume of water in the graduated cylinder: 75.0 mL
Step 2: Calculate the volume of the lead fishing weight
The density of lead is 11.34 g/mL.
39.7 g × (1 mL/11.34 g) = 3.50 mL
Step 3: Calculate to what volume will increase the water level
The final volume of water will be equal to its initial value plus the volume displaced by the lead fishing weight.
V = 75.0 mL + 3.50 mL = 78.5 mL
142 kg in grams:
1 kg ---------- 1000 g
142 kg -------- ?
142 x 1000 / 1 => 142000 g
Atomic mass Cu = 63.54 a.m.u
Therefore:
63.54 g ------------ 6.02x10²³ atoms
142000 g --------- ??
142000 x ( 6.02x10²³) / 63.54 =
8.54.10²⁸ / 63.54 => 1.34.10²⁷ atoms of Cu
Answer : The partial pressure of is 102.3 mmHg.
Explanation :
As per question,
Mass of = 62.9 g
Mass of = 33.2 g
Molar mass of = 18 g/mole
Molar mass of = 62 g/mole
First we have to calculate the moles of and .
Now we have to calculate the mole fraction of and .
Now we have to partial pressure of .
According to the Raoult's law,
where,
= partial pressure of water vapor
= total pressure of gas
= mole fraction of water vapor
Therefore, the partial pressure of is 102.3 mmHg.
Answer:
The answer to your question is: A.
Explanation:
A. C + 2H₂ ⇒ CH₄ This is the right answer because the equation is balanced and is according to the law of conservation of matter.
B. 2H₂ + O₂ ⇒ NH₃ This option is wrong because in the reactants there is oxygen and it is not in the products.
C. 2Al₂O₃ ⇒ 2Na₂O This equation is not according to the law of conservation of matter, in the reactants there is aluminum and it is not in the products.
D. N₂ + 3H₂ ⇒ P₄O₁₀ This equation is not according to the law of conservation of matter.
<span>There are two atoms of sodium and one atom of oxygen. lmk if its right or wrong</span>