Answer:
Number of moles
Explanation:
Using the number of moles in chemical reactions, we can determine the quantity of products and even the reactants that are combining to form them.
The number of moles is derived using the expression below is;
Number of moles =
Once we establish the number of moles of any of the specie given from the mass and molar mass, we can relate it to any other species.
The question is incomplete , complete question is:
Hydrogen, a potential future fuel, can be produced from carbon (from coal) and steam by the following reaction:
Note that the average bond energy for the breaking of a bond in CO2 is 799 kJ/mol. Use average bond energies to calculate ΔH of reaction for this reaction.
Answer:
The ΔH of the reaction is -626 kJ/mol.
Explanation:
We are given with:
ΔH = (Energies required to break bonds on reactant side) - (Energies released on formation of bonds on product side)
The ΔH of the reaction is -626 kJ/mol.
Answer
A)The volume decreases by a factor of 4
B), the volume has increased by factor of 2
Explanation:
A)Given:
P1= 760Kpa
P2 =202Kpa
The temperature changes from37C to155C
There is increase In pressure from P1 to P2
P1= 760torr.
We need to convert to Kpa
But, 1atm= 760torr
Then 760torr 101000pa
Then 101000pa = 101Kpa
We need to convert the temperature from Celsius to Kelvin
T1= 37+273= 310K
But from ideal gas, we know that PV = nRT where nR is constant
Where P= pressure
V= volume
T= temperature
n = number of moles
(P1V1/T1)=(P2V2/T2)
V1/V2 = P2/P1 * T1/T2
V1/V2 = (202/101)*(310/155)
V1/V2=4
Therefore, the volume has decreased by factor of 4
B)
Given:
P1= 2atm
P2 =101Kpa
The temperature changes from 305K to 32C
There is increase In pressure from P1 to P2
P1= 2atm
We need to convert to Kpa
But, 1atm= 760torr
Then 760torr 101000pa
Then 101000pa = 101Kpa
P1= 202.65kpa
We need to convert the temperature from Celsius to Kelvin
T2= 32+273= 305K
But from ideal gas, we know that PV = nRT
Where P= pressure
V= volume
T= temperature
n = number of moles
(P1V1/T1)=(P2V2/T2)
V1/V2 = P2/P1 * T1/T2
V1/V2 = (202/101)
V1/V2 = (101/202.65)*(305/305)
V1/V2 = 1/2
Therefore, the volume has increased by factor of 2