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Semenov [28]
2 years ago
11

N₂(g) + 3H₂(g) → 2NH3(g)

Chemistry
1 answer:
Anna71 [15]2 years ago
8 0

Answer:

93.5 moles N₂

Explanation:

To find the moles, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = number of moles

-----> R = constant (0.0821 atm*L/mol*K)

-----> T = temperature (K)

You can plug the given values into the equation and simplify to find moles. The final answer should have 3 sig figs to match the lowest number of sig figs among the given values.

P = 95.0 atm                  R = 0.0821 atm*L/mol*K

V = 224 L                       T = 2773 K

n = ?

PV = nRT

(95.0 atm)(224 L) = n(0.0821 atm*L/mol*K)(2773 K)

21280 = n(227.6633)

93.5 = n

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oee [108]

Answer:

x = 0.324 M s⁻¹

Explanation:

Equation for the reaction can be represented as:

 2 NO(g)   + Cl₂ (g)      ⇄     2NOCl (g)

Rate = K [NO]² [Cl₂]

Concentration = \frac{numbers of mole (n)}{volume (v)}

from the question; their number of moles are constant since the species are quite alike.

As such; if Concentration varies inversely proportional to the volume;

we have: Concentration ∝ \frac{1}{v}

Concentration = \frac{1}{v}

Similarly; the Rate can now be expressed as:

Rate = K [NO]² [Cl₂]

Rate = (\frac{1}{v}) ^2 (\frac{1}{v} )

Rate = \frac{1}{v^3}

We were also told that the in the reaction, the gaseous system has an initial volume of 3.00 L and rate of formation of 0.0120 Ms⁻¹

So we can have:

0.0120 = \frac{1}{3^3}

0.0120 = \frac{1}{27}   -----Equation (1)

Now; the new rate of formation when the  volume of the system decreased to 1.00 L can now be calculated as:

x = (\frac{1}{1})^3

x = 1             ------- Equation (2)

Dividing equation (2) with equation (1); we have:

\frac{0.0210}{x} = \frac{\frac{1}{27} }{1}

\frac{0.0210}{x} = \frac{1}{27}

x = 0.0120 × 27

x = 0.324 M s⁻¹

∴  the new rate of formation of NOCl = 0.324 M s⁻¹

8 0
3 years ago
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what temperature will 215 mL of a gas at 20°C and 1 atm pressure attain when it is subject to 1.5 atm of pressure?
romanna [79]

<u>Given:</u>

Volume of gas = 215 ml

Initial temperature T1 = 20C = 20 +273 = 293 K

Initial pressure P1 = 1 atm

Final pressure P2 = 1.5 atm

<u>To determine:</u>

The final temperature T2

<u>Explanation:</u>

Based on Gay-Lussac's Law:

P α T

Therefore we have the relation:

P1/T1 = P2/T2

T2 = P2T1/P1 = 1.5 *293/1 = 439.5 K

Converting from Kelvin to degrees C we have:

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When electricity is passed through a common salt solution. Sodium hydroxide is
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Answer:

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