Its lithosphere, because lithosphere is above asthenosphere
Thunder is caused by the extremely rapid expansion of air around a bolt of lightning due to the very high temperature. It is also caused by the change of pressure around a lightning bolt.
Hope that helped you.
Answer:
The cross is as follows:
P: D/d × d/d
Explanation:
Half of the F1 progeny are mutant. The mutation results in 3 cotyledons is dominant and the original mutant is heterozygous.
If D denotes the mutant allele and d denotes the wild type allele.
The cross is as follows:
P: D/d × d/d
F1 denotes D/d three cotyledons
d/d denote two cotyledons
Answer:
Information and a couple of other people who is interested in taking up and taking a role away the home.
Explanation:
ami koice amar apnara thara dakta the the beautiful studies you speech block ever the thing studies opportunity for the next level ta the first thing that I have to go shafil is the right answer which is why it was worse than usual in order for my sister henna video games and the family is the comparative narrow and the family will not complete this picture I have to call the police and they said they would be found by him.
Answer:
1. G° = -RT ln (G1P/P)
3.1 = 8.314 × 310 × ln (G1P/P)
3.1 / 2577.34 = ln (G1P/P)
0.0012 = ln (G1P/P)
0.0012 = (log G1P/P)/log 2.71828
0.4342 × 0.0012 = log G1P/P
0.00052 = log G1P/P
G1P/P = 10^0.00052 = 1.0012
P/G1P = 1/1.0012 = 0.9988
2. The cleavage of glycogen phosphorolytically is beneficial for the cell to conduct the process as the discharged glucose is phosphorylated. A general hydrolytic cleavage would give rise to only a glucose, which has to be phosphorylated again with the help of ATP.
Another merit of phosphorylated glucose is that it comprises the negative charge and cannot diffuse out of the muscle cell. Thus, the reaction will not be at equilibrium under the physiological conditions and always encourages the generation of the products. The formation of products will amend the change in free energy in such a manner that the reaction will always carry in the forward direction.
3. Greater the ratio of [Pi]/[glucose-1-phosphate], higher will be the relative rate of glycogen phosphorylase in comparison to the phosphoglucomutase as the transformation of Glu-1-P becomes slow because of lesser accessibility of substrate.
