Answer:
The child has 6 dimes and 5 quarters.
Step-by-step explanation:
Let q and d represent the number of quarters and of dimes respectively.
Then q + d = 11 (Equation A), and ($0.25/quarter)q + ($0.10/dime)d = $1.85 (Equation B).
Multiply the 2nd equation by 100 to remove the decimal fractions:
25q + 10d = 185 (Equation C)
Now multiply the 1st equation by -10 to obtain -10q - 10d = -110 (Equation D), and combine this result with Equation C:
-10q - 10d = -110
25q + 10d = 185
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15q = 75, and so q = 75/15 = 5.
According to Equation A, q + d = 11. Replacing q with 5, we get:
5 + d = 11, and so d = 6.
The child has 6 dimes and 5 quarters.
Area of triangle = <em>A(t) </em>= 1/2(base x height)
Area of square = <em>A(s) = </em>base x height
<em>A(s) </em>= 2 x 2 = 4
<em>2(A(s))</em> = 2(1/2(2)(2) = 2(1/2(4)) = 2(2) = 4
Add the two areas together
4 + 4 = 8
8 units² is your answer
I think it’s between 100-200 like 150 cause it’s near a 100 and more then a 100 too.
Let x be the original position.
After the first play they gain 9 yards. The position can be represented by
x + 9
After the second play they lose 22 yards. The position can be represented by
x + 9 - 22 = x - 13
Therefore, in total they lost 13 yards.
