Hi someone plsss help me

Chemistry

1 answer:

diamong [38]3 years ago

6 0

Explanation: I cant see the picture

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How would you prepare 1 liter of .030 m copper 2 sulfate pentahydrate?

Ierofanga [76]

Answer is: dissolve 74,9 grams CuSO₄·5H₂O in one liter volumetric flask.
V(CuSO₄·5H₂O) = 1 L.
c(CuSO₄·5H₂O) = 0,30 mol/L.
n(CuSO₄·5H₂O) = V(CuSO₄·5H₂O) · c(CuSO₄·5H₂O) .
n(CuSO₄·5H₂O) = 1 L · 0,3 mol/L.
n(CuSO₄·5H₂O) = 0,3 mol.
m(CuSO₄·5H₂O) = n(CuSO₄·5H₂O) · M(CuSO₄·5H₂O).
m(CuSO₄·5H₂O) = 0,3 mol · 249,7 g/mol.
m(CuSO₄·5H₂O) = 74,9 g.

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3 years ago

You have a 10 gram piece of aluminum and a 10 gram piece of gold sitting in the sun which piece of metal will warm by ten degree

Yuki888 [10]

Answer:

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Explanation:

Because gold has a lower specific heat than aluminium.

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4 years ago

Draw the best lewis structure for bro4- and determine the formal charge on bromine

Svetach [21]

Answer :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule. The electrons are represented by dot.

The given molecule is, perbromate ion.

Bromine has '7' valence electrons and oxygen has '6' valence electron.

Therefore, the total number of valence electrons in perbromate ion, $BrO_4^-$ = 7 + 4(6) + 1 = 32