<span>The velocity would be 54.2 m/s
We would use the equation 1/2mv^2top+mghtop = 1/2mv^2bottom+mghbottom where m is the mass of the bobsled(which can be ignored), vtop/bottom is the velocity of the bobsled at the top or bottom, g is gravity, and htop/bottom is the height of the bobsled at the top or bottom of the hill. Since the velocity of the bobsled at the top of the hill and height at the bottom of the hill are zero, 1/2mv^2top and mghbottom will equal zero. The equation will be mghtop=1/2mv^2bottom. Thus we would solve for v.</span>
<span>This spectrometer reading shows some red, blue, and purple. Our atom is most likely Hydrogen source.
This spectrometer reading shows some reds, orange, and yellow. Our atom is most likely Neon source.
This spectrometer reading shows some red, yellow, and blue. Our atom is most likely Helium source.
This spectrometer reading shows some yellow, blue, and purple. Our atom is most likely Mercury source</span>
Answer:
- the expected value is 8
- the standard deviation is 2.8284
Explanation:
Given the data in the question;
The model N(t), the number of planets found up to time t, as a poisson process,
∴ N(t) has distribution of poisson distribution with parameter (λt)
so
the mean is;
λ = 1 every month = 1/3 per month
E[N(t)] = λt
E[N(t)] = (1/3)(24)
E[N(t)] = 8
Therefore, the expected value is 8
For poisson process, Variance and mean are the same,
Var[N(t)] = Var[N(24)]
Var[N(t)] = E[N(24)]
Var[N(t)] = 8
so the standard deviation will be;
σ[N(24)] = √(Var[N(t)] )
σ[N(24)] = √(8 )
σ[N(24)] = 2.8284
Therefore, the standard deviation is 2.8284
Answer:
Velocity = 0.5 m/s South (A)
Explanation:
You need to determine the average rate of velocity.
The equation you will use is velocity = displacement/time
The displacement is 30m South.
The time is 60 seconds.
Plug into the equation Velocity = 30m South/60 s
Velocity = 0.5 m/s South
The speed of sound at

is approximately v=343 m/s. The distance covered by the sound wave is

And the time it takes is

Now we want to find how far the light travels during this time. Light travels at speed

, therefore the distance it covers during this time is