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den301095 [7]
3 years ago
15

An object has an acceleration of 6.0 m/s/s. If the net force was doubled and the mass was one-third the original value, then the

new acceleration would be _____ m/s/s.
Physics
1 answer:
alexandr402 [8]3 years ago
5 0

Hahahahaha. Okay.

So basically , force is equal to mass into acceleration.

F=ma

so when F=ma , we get acceleration=6m/s/s

Force is doubled.

Mass is 1/3 times original.

2F=1/3ma

Now , we rearrange , and we get 6F=ma

So , now for 6 times the original force , we get 6 times the initial acceleration.

So new acceleration = 6*6= 36m/s/s

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Answer:

7 m/s²

Explanation:

From the question given above, the following data were:

Force applied (Fₐ) = 15 N

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Acceleration (a) of block =?

Next, we shall determine the frictional force. This can be obtained as follow:

Mass (m) of block = 1.5 Kg

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Normal reaction (R) = mg = 1.5 × 10 = 15 N

Frictional force (Fբ) =?

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Fբ = 0.3 × 15

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Next, we shall determine the net force acting on the block. This can be obtained as follow:

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