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Maslowich
2 years ago
15

On a drive from one city to? another, victor averaged 39 mph. if he had been able to average 72 ?mph, he would have reached his

destination 11 hrs earlier. what is the driving distance between one city and the? other?
Physics
1 answer:
PilotLPTM [1.2K]2 years ago
5 0
Let the unknown distance be xmiles
x/39-x/72=11hr
72x-39x/2808=11hr
33x/2808=11
33x= 30888
x=936miles
U can substitue back to check
at speed of 72mph, he would need 936/72=13hrs
at speed of 39mph, he would need 936/39=24hr
the difference is 24-13=11
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A 50.0-kg projectile is fired at an angle of 30 degrees above thehorizontal with an initial speed of 1.20 x 102 m/s fromthe top
Advocard [28]

Answer:

a)  Em₀ = 42.96 104 J , b)   W_{fr} = -2.49 105 J , c)  vf = 3.75 m / s

Explanation:

The mechanical energy of a body is the sum of its kinetic energy plus the potential energies it has

        Em = K + U

a) Let's look for the initial mechanical energy

      Em₀ = K + U

      Em₀ = ½ m v2 + mg and

      Em₀ = ½ 50.0 (1.20 102) 2 + 50 9.8 142

      Em₀ = 36 104 + 6.96 104

      Em₀ = 42.96 104 J

b) The work of the friction force is equal to the change in the mechanical energy of the body

    W_{fr} = Em₂ -Em₀

     Em₂ = K + U

     Em₂ = ½ m v₂² + m g y₂

     Em₂ = ½ 50 85 2 + 50 9.8 427

     Em₂ = 180.625 + 2.09 105

     Em₂ = 1,806 105 J

     W_{fr} = Em₂ -Em₀

     W_{fr} = 1,806 105 - 4,296 105

     W_{fr} = -2.49 105 J

The negative sign indicates that the work that force and displacement have opposite directions

c) In this case the work of the friction going up is already calculated in part b and the work of the friction going down would be 1.5 that job

We have that the work of friction is equal to the change of mechanical energy

       W_{fr} = ΔEm

       W_{fr} = Emf - Emo

       -1.5 2.49 10⁵ = ½ m vf² - 42.96 10⁴

       ½ m vf² = -1.5 2.49 10⁵ + 4.296 10⁵

       ½ 50.0 vf² = 0.561

       vf = √ 0.561 25

      vf = 3.75 m / s

6 0
3 years ago
What is the difference between professional and casual communication styles?
Lady bird [3.3K]

Answer:

professional communication style is expected to be formal while the casual is informal.

Explanation:

7 0
2 years ago
he capacitor can withstand a peak voltage of 550 VV . If the voltage source operates at the resonance frequency, what maximum vo
anygoal [31]

Answer:

The maximum voltage is 39.08 V.

Explanation:

Given that,

Voltage = 550 V

Suppose, In an L-R-C series circuit, the resistance is 400 ohms, the inductance is 0.380 Henry, and the capacitance is 1.20\times10^{-2}\mu F

We need to calculate the resonant frequency

Using formula of resonant frequency

f=\dfrac{1}{2\pi\sqrt{LC}}

Put the value into the formula

f=\dfrac{1}{2\pi\sqrt{0.380\times1.20\times10^{-8}}}

f=2356.8\ Hz

We need to calculate the maximum current

Using formula of current

I=\dfrac{V_{c}}{X_{c}}

I=2\pi f C\times V_{c}

Put the value into the formula

I=2\pi\times2356.8\times1.20\times10^{-8}\times550

I=0.0977\ A

We need to calculate the impedance of the circuit

Using formula of impedance

Z=\sqrt{R^2+(X_{L}-X_{C})^2}

At resonant frequency , X_{L}=X_{C}

So, Z = R

We need to calculate the maximum voltage

Using formula of voltage

V=IR

Put the value into the formula

V=0.0977\times400

V=39.08\ V

Hence, The maximum voltage is 39.08 V.

4 0
3 years ago
sound of thunder is heard 5s after the flash of lighting is seen. calculate the distance of nearest point of lighting if the spe
Karolina [17]

Answer:

formula

speed = distance / time

distance = speed x time

distance = 346 x 5

distance = 1730 m

The distance of the lightening strike would be 1730 m or 1.7 km

Explanation:

6 0
3 years ago
Read 2 more answers
After an initial test run John determines that his cooling system generates 45 W of heat loss. Calculate the amount of heat loss
anyanavicka [17]

Given:

heat generated by John's cooling system,  H = \rho A v^{3}  = 45 W    (1)

If ρ, A, and v corresponds to John's cooling system then let \rho_{1}, A_{1}, v_{1} be the variables for Mike's system then:

\rho  = 9.5\rho_{1}

\rho_{1}  = \frac{\rho}{9.5}

v_{1} =3.5 v

Formula use:

Heat generated, H = \rho A v^{3}

where,

\rho = density

A = area

v = velocity

Solution:

for Mike's cooling system:

H_{2} = v_{1}^{3}{1}A_{1}\rho_{1}

⇒ H_{2} = (3.5v)^{3} × A × \frac{\rho}{9.5}

H_{2} = 4.513v^{3} A  \rho

Using eqn (1) in the above eqn, we get:

H_{2} = 4.513 × 45 = 203.09 W

5 0
2 years ago
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