How much in kg is 1 N
1 answer:
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Answer:
F = 0.078N
Explanation:
In order to calculate the magnitude of the force on the wire you first calculate the magnitude of the magnetic field generated by the solenoid, by using the following formula:
(1)
μo: magnetic permeability of vacuum = 4π*10^-7 T/A
N: turns of the solenoid = 580
i: current in the solenoid = 36A
L: length of the solenoid = 18cm = 0.18m
You replace the values of all parameters in the equation (1):
Next, you calculate the force exerted on the wire, by using the following formula:
(2)
i: current in the wire = 27A
L: length of the wire that perceives the magnetic field (the same as the radius of the solenoid) = 2.0 cm = 0.02m
θ: angle between wire and the direction of B
B: magneitc field in the solenoid = 0.145T
The direction of the wire are perpendicular to the direction of the magnetic field, hence, the angle is 90°.
You replace the values of the parameters in the equation (2):
The magnitude of the force on the wire is 0.078N
Since energy cannot be created nor destroyed, the change in energy of the electron must be equal to the energy of the emitted photon.
The energy of the emitted photon is given by:
where
h is the Planck constant
f is the photon frequency
Substituting
, we find
This is the energy given to the emitted photon; it means this is also equal to the energy lost by the electron in the transition, so the variation of energy of the electron will have a negative sign (because the electron is losing energy by decaying from an excited state, with higher energy, to the ground state, with lower energy)
The energy of the emitted photon is given by:
where
h is the Planck constant
f is the photon frequency
Substituting
This is the energy given to the emitted photon; it means this is also equal to the energy lost by the electron in the transition, so the variation of energy of the electron will have a negative sign (because the electron is losing energy by decaying from an excited state, with higher energy, to the ground state, with lower energy)