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3 years ago

13

Which of the following was not a famous basketball player for the NBA? Select one: a. Wilt Chamberlain b. Lady Bird Johnson c. M

ichael Jordan d. Magic Johnson

1 answer:

DiKsa [7]3 years ago

3 0

Answer:

B Lady Bird Johnson

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Rosa records the distance that a toy car rolls and the time it takes to cover the distance. What scientific practice is this?

Sergio039 [100]

Rosa is conducting the scientific practice of observation.

3 0

3 years ago

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Light of wavelength 550 nm comes into a thin slit and produces a diffraction pattern on a board 8.0 m away. The first minimum da

FrozenT [24]

Answer:

Width of the slit will be equal to 1.47 mm

Explanation:

We have given wavelength of the light $\lambda =550nm=550\times 10^{-9}m$

Distance D = 8 m

Distance between first minimum dark fringe and the central maximum is 2 mm

So $x=3\times 10^{-3}m$

We have to find the width of the slit

For the first order wavelength is equal to $\lambda =\frac{x}{D}\times a$ , here a width of slit

So $a=\frac{\lambda D}{x}=\frac{550\times 10^{-9}\times 8}{3\times 10^{-3}}=1466.666\times 10^{-6}=1.47mm$

So width of the slit will be equal to 1.47 mm

5 0

3 years ago

A satellite is orbiting the earth. If a payload of material is added until it doubles the satellite's mass, the earth's pull of

dimulka [17.4K]

Answer:

True

Explanation:

When a satellite is orbiting the earth, the centripetal force is balanced by the gravitational force as :

$\dfrac{GMm}{r^2}=\dfrac{mv^2}{r}$

$v=\sqrt{\dfrac{GM}{r}}$ ...........(1)

Where

M is the mass of the earth

m is the mass of the planet

From equation (1), the speed of the satellite depends only on the mass of the earth and the orbital radius.

So, If a payload of material is added until it doubles the satellite's mass, the earth's pull of gravity on this satellite will double but the satellite's orbit will not be affected. It is true.

6 0

3 years ago

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A particular roller coaster has a mass of 3500 kg, a height of 4.0 m, and a velocity of 12 m/s. What is the kinetic energy? If n

Alenkinab [10]

Explanation:

given

m=3500kg,h=4.0m,v=12m/s

ke=½mv²

½×3500×12²=3500×144÷2

=252,000j or 252j

8 0

2 years ago

Suppose astronomers discover a radio message from a civilization whose planet orbits a star 35 light-years away. Their message e

Grace [21]

Answer:

The duration is $T =72 \ years /tex]Explanation:From the question we are told that The distance is [tex]D = 35 \ light-years = 35 * 9.46 *10^{15} = 3.311 *10^{17} \ m$

Generally the time it would take for the message to get the the other civilization is mathematically represented as

$t = \frac{D}{c}$

Here c is the speed of light with the value $c = 3.08 *10^{8} \ m/s$

=> $t = \frac{3.311 *10^{17} }{3.08 *10^{8}}$

=> $t = 1.075 *10^9 \ s$

converting to years

$t = 1.075 *10^9 * 3.17 *10^{-8}$

$t = 1.075 *10^9 * 3.17 *10^{-8}$

$t = 34 \ years$

Now the total time taken is mathematically represented as

$T = 2* t + 2 + 2$

=> $T = 2* 34 + 2 + 2$

=> [tex]T =72 \ years /tex]

4 0

3 years ago