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Setler [38]
2 years ago
11

Assuming a mass of 0.04 g, what is the power exerted by the electrical forces on a fragment of fiber if the fragment has a veloc

ity of 200 mm/s, 10 ms after ejection? For this problem, I used the formula P= Force * velocity = mass* (velocity/time)*velocity = (mass * velocity^2) /time. However I got the problem wrong. In the answer, they used the formula P= W/t = 1/2* (mass*velocity^2)/time. I am confused.When do you use P = Force * velocity = (mass * velocity^2) /time and when do you use P= W/t = 1/2* (mass*velocity^2)/time?
Physics
1 answer:
schepotkina [342]2 years ago
8 0

The power exerted by the electrical forces on a fragment of fiber is 8.0× 10^-5 Watts

<h3>Power and Energy or Work done</h3>

Power is the rate of doing work.

  • Power = work done / time

Energy is the ability to do work.

Work done and energy are used interchangeably.

  • Work done = Force × distance

In the example above, the energy possessed by the mass is kinetic energy.

Kinetic energy is the energy a body has by virtue of its motion.

  • Kinetic energy, KE = 1/2 mv^2

Calculating kinetic energy of the body:

mass of the body = 0.04 g = 4.0 × 10^-5 kg

velocity of the body = 200mm/s = 0.2 m/s

Kinetic energy of the body = 1/2 × 4.0 × 10^-5 × 0.2^2

Kinetic energy of the body = 8.0× 10^-7

Thus, work done = 8.0× 10^-7 J

Calculating power exerted:

time taken = 10 ms = 0.01 s

Power = work done/ time

Power exerted = 8.0× 10^-7/0.01

Power exerted = 8.0× 10^-5 Watts

Therefore, the power exerted by the electrical forces on a fragment of fiber is 8.0× 10^-5 Watts

Learn more about about electrical energy and power at: brainly.com/question/60890

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The final temperature of the system will be equal to the initial temperature, and which is 373K. The work done by the system is 409.8R Joules.

To find the answer, we need to know about the thermodynamic processes.

<h3>How to find the final temperature of the gas?</h3>
  • Any processes which produce change in the thermodynamic coordinates of a system is called thermodynamic processes.
  • In the question, it is given that, the tank is rigid and non-conducting, thus, dQ=0.
  • The membrane is raptured without applying any external force, thus, dW=0.
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<h3>What is a reversible process?</h3>
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Thus, we can conclude that, the final temperature of the system will be equal to the initial temperature, and which is 373K. The work done by the system is 409.8R Joules.

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