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Nadya [2.5K]
4 years ago
10

A uniform solid ball rolls smoothly along a floor, then up a ramp inclined at 15.2 o. It momentarily stops when it has rolled 2.

00 m along the ramp. What was its initial speed?
Physics
1 answer:
inysia [295]4 years ago
8 0

Answer:

v \approx 3.207\,\frac{m}{s}

Explanation:

Let assume that ball's motion is frictionless and its geometric dimensions can be neglected. Besides, it is assumed that ball begins at a height of zero. The ball can be modelled by means of the Principle of Energy Conservation:

K_{A} = U_{g}

\frac{1}{2}\cdot m \cdot v^{2} = m \cdot g \cdot h

v = \sqrt{2\cdot g \cdot h}

v = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot (2\,m)\cdot \sin 15.2^{\textdegree}}

The initial speed of the ball is:

v \approx 3.207\,\frac{m}{s}

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The question is incomplete. The complete question is :

Two loudspeakers are placed 1.8 m apart. They play tones of equal frequency. If you stand 3.0 m in front of the speakers, and exactly between them, you hear a minimum of intensity. As you walk parallel to the plane of the speakers, staying 3.0 m away, the sound intensity increases until reaching a maximum when you are directly in front of one of the speakers. The speed of sound in the room is 340 m/s.

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