Stress required to cause slip on in the direction [ 1 1 0 ] is 7.154 MPa
<u>Explanation:</u>
Given -
Stress Direction, A = [1 0 0 ]
Slip plane = [ 1 1 1]
Normal to slip plane, B = [ 1 1 1 ]
Critical stress, Sc = 2.92 MPa
Let the direction of slip on = [ 1 1 0 ]
Let Ф be the angle between A and B
cos Ф = A.B/ |A| |B| = [ 1 0 0 ] [1 1 1] / √1 √3
cos Ф = 1/√3
σ = Sc / cosФ cosλ
For slip along [ 1 1 0 ]
cos λ = [ 1 1 0 ] [ 1 0 0 ] / √2 √1
cos λ = 1/√2
Therefore,
σ = 2.92 / 1/√3 1/√2
σ = √6 X 2.92 MPa = 2.45 X 2.92 = 7.154MPa
Therefore, stress required to cause slip on in the direction [ 1 1 0 ] is 7.154MPa
Compounds are formed as a result of elements that are joined and held together by strong forces called chemical bonds.
Answer:
an electromagnetic wave with a wavelength in the range 0.001–0.3 m, shorter than that of a normal radio wave but longer than those of infrared radiation. Microwaves are used in radar, in communications, and for heating in microwave ovens and in various industrial processes.
Answer:
Weight on Earth = We = 186.2 N
Weight on Mars = Wm = 70.94 N
Explanation:
The weight of an object is defined as the force applied on the object by the gravitational field. The magnitude of weight is given by the following formula:
W = mg
were,
W= Weight of Eric
m = mass of Eric
g = acceleration due to gravity
ON EARTH:
W = We = Eric's Weight on Earth = ?
m = Eric's Mass on Earth = 19 kg
ge = acceleration due to gravity on Earth = 9.8 m/s²
Therefore,
We = (19 kg)(9.8 m/s²)
<u>We = 186.2 N</u>
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ON MARS:
W = Wm = Eric's Weight on Mars = ?
m = Eric's Mass on Mars = 19 kg
gm = acceleration due to gravity on Mars = 0.381(ge) = (0.381)9.8 m/s² = 3.733 m/s²
Therefore,
Wm = (19 kg)(3.733 m/s²)
<u>Wm = 70.94 N</u>