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2 years ago

What is 0.002 represented by

Physics

2 answers:

aleksandr82 [10.1K]2 years ago

7 0

Scientific notation

Helga [31]2 years ago

6 0

I think you want 2x10^-2
It’s called Scientific Notation

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A two-turn circular wire loop of radius 0.63 m lies in a plane perpendicular to a uniform magnetic field of magnitude 0.219 T. I

Basile [38]

Answer:

The magnitude of the average induced emf in the wire during this time is 9.533 V.

Explanation:

Given that,

Radius r= 0.63 m

Magnetic field B= 0.219 T

Time t= 0.0572 s

We need to calculate the average induce emf in the wire during this time

Using formula of induce emf

$E=-\dfrac{d\phi}{dt}$

$E=-B\dfrac{dA}{dt}$

$E=-B\dfrac{A_{2}-A_{1}}{dt}$

$E=B\dfrac{A_{1}-A_{2}}{dt}$ .....(I)

In reshaping of wire, circumstance must remain same.

We calculate the length when wire is in two loops

$l=2\times 2\pi\times r_{1}$

$l=2\times 2\pi\times 0.63$

$l=7.916\ m$

The length when wire is in one loop

$l=2\pi\times r_{2}$

$7.916=2\times \pi\times r_{2}$

$r_{2}=\dfrac{7.916}{2\times \pi}$

$r_{2}=1.259\ m$

We need to calculate the initial area

$A_{1}=N\times\pi\times r_{1}^2$

Put the value into the formula

$A_{1}=2\times3.14\times(0.63)^2$

$A_{1}=2.49\ m^2$

The final area is

$A_{2}=N\times\pi\times r_{2}^2$

$A_{2}=1\times\pi\times(1.259)^2$

$A_{2}=4.98\ m^2$

Put the value of initial area and final area in the equation (I)

$E=0.219\dfrac{2.49-4.98}{0.0572}$

$E=-9.533\ V$

Negative sign shows the direction of induced emf.

Hence, The magnitude of the average induced emf in the wire during this time is 9.533 V.

6 0

3 years ago

The acceleration of a particle is given by a = 6t - 28, where a is in meters per second squared and t is in seconds. Determine t

baherus [9]

Answer:

Velocity, V = 3t²- 28t+6

Displacement, s = t³ - 14t²+6t -8

At t = 5.8 s

s = -249.05 m

v = -55.48 m/s

At t = 12.7 s

s = -141.48 m

v = 134.27 m/s

Explanation:

We have acceleration of a particle is given by a = 6t - 28

Velocity

$v=\int adt=\int (6t - 28)dt=3t^2-28t+C$

At t = 0 we have v₀ = 6 m/s

v₀ = 6 = 3 x 0 ²-28 x 0+C

C = 6

So velocity, V = 3t² - 28t+6

Displacement

$s=\int vdt=\int (3t^2-28t+6)dt=t^3-14t^2+6t+C$

At t = 0 we have s₀ = -8 m

s₀ = -8 = 0³ + 14 x 0² + 6 x 0 + C

C = -8

So displacement, s = t³ - 14t²+6t -8

At t = 5.8 s

s = 5.8³ - 14 x 5.8²+6 x 5.8 - 8 = -249.05 m

v = 3 x 5.8² - 28 x 5.8 + 6 = -55.48 m/s

At t = 12.7 s

s = 12.7³ - 14 x 12.7²+6 x 12.7 - 8 = -141.48 m

v = 3 x 12.7² - 28 x 12.7 + 6 = 134.27 m/s

4 0

3 years ago

Which of the following is least likely to result from seafloor spreading

Assoli18 [71]

Answer:

An reversal in the magnetic fields of the north and south pole. This would be the most logical option for me...correct me if I'm wrong.

Explanation:

New seafloor is formed when magma is forced upward toward the surface at a mid-ocean.

7 0

3 years ago

How do you calculate mass using Newton’s 2nd Law?

deff fn [24]

The 2nd Law says F=ma, where F is the force in Newtons, m is mass and a is acceleration. Earth's gravity is an acceleration, 9.8m/s^2. So you can solve the equation for mass, m=F/a, or m=F/9.8 where you've measured the force (weight) in Newtons.

5 0

3 years ago

Read 2 more answers

Item 19 Question 1 A Ferris wheel has a radius of 75 feet. You board a car at the bottom of the Ferris wheel, which is 10 feet a

sergey [27]

Answer:

$y = 104.4 ft$

Explanation:

As we know that we board in the car of ferris wheel at the bottom position

So we will have

final height of the car at angular displacement given as

$y = y_o + R + R sin(270 - 255)$

$y = y_o + R + R sin 15$

here we know that

$y_o = 10 ft$

$R = 75 ft$

so we have

$y = 10 + 75 + 75 sin15$

$y = 104.4 ft$

4 0

3 years ago