<span>At a corner gas station, the revenue R varies directly with the number g of gallons of gasoline sold. If the revenue is $44.50 when the number of gallons sold is 10, find a linear equation that relates revenue R to the number g of gallons of gasoline. Then find the revenue R when the number of gallons of gasoline sold is 15.5.
Solution:
As the question mentioned the direct relationship between the quantities, hence
10 gallons of gasoline sold = $44.50
15.5 gallons of gasoline sold = $x
by cross multiplication, we get that
10x = 15.5 * 44.50
which implies that
x = 68.975
Thus by $</span>68.975 revenue is obtained by selling 15.5 gallons of gasoline.
Answer:
64
Step-by-step explanation:
(9-1)^5 / (6+2)^3
8^5 / 8^3
32768 / 512
64
Answer:
Step-by-step explanation:
<u>Let </u>
x = 3.777....... (1)
<u>Then </u>
10x = 37.777..... (2)
Subtracting (1) from (2)
10x - x = 37.7777..... - 3.77777.......
9x = 34
Dividing both sides by 9
x = 34 / 9
x = 
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h2>~AnonymousHelper1807</h2>
There were 120 hamburgers.
EXPLANATION: The two equations would be y=-x+480 and 3y=x; y meaning hamburgers and x meaning cheeseburgers. If you put both of the equations on top of each other and add them you get 4y=480, which means y=120.
