Answer:
approximate 23.590 feet
Step-by-step explanation:
tan 65° = x / 11 = 2.145
x = 11 x 2.145 = 23.595
Answer:
i think you are missing something
Step-by-step explanation:
Hey there!
1.21 repeating as a fraction is 40/33.
Hope this was of help, have a great day :)
The sample space of an event is the list of possible elements of the event.
The set elements are:
- Ac = {x : 0, 5 ≤ x ≤ 10}
- A n B = {x : 3 ≤ x ≤ 4}
- A ∪ B = {x : 0 < x ≤ 7}
- A∩Bc = {x : 1 ≤ x ≤ 2}
- A^c ∪ B = {x : 0, 3 ≤ x ≤ 10}
<h3>How to determine the intervals of the subsets</h3>
The given parameters are:
S = {x : 0 ≤ x ≤ 10}
A = {x : 0 < x < 5}
B = {x : 3 ≤ x ≤ 7}
<u>(a) Ac </u>
This represents the list of elements in the universal set not in set A.
So, we have:
Ac = {x : 0, 5 ≤ x ≤ 10}
<u>(b) A ∩ B </u>
This represents the list of common elements in sets A and set B.
So, we have:
A n B = {x : 3 ≤ x ≤ 4}
<u>(c) A ∪ B </u>
This represents the list of all elements in sets A and set B, without repetition.
So, we have:
A ∪ B = {x : 0 < x ≤ 7}
<u>d) A∩Bc </u>
Given that:
B = {x : 3 ≤ x ≤ 7}
So, we start by calculating B^c i.e. the list of elements in the universal set not in set B.
So, we have:
Bc = {x : 1, 2, 8 ≤ x ≤ 10}
A∩Bc would then represent the list of common elements in sets A and set Bc
So, we have:
A∩Bc = {x : 1 ≤ x ≤ 2}
<u>(e) A^c ∪ B</u>
In (a), we have:
Ac = {x : 0, 5 ≤ x ≤ 10}
Given that:
B = {x : 3 ≤ x ≤ 7}
A^c ∪ B would then represent the list of all elements in sets Ac and set B
So, we have:
A^c ∪ B = {x : 0, 3 ≤ x ≤ 10}
Read more about sets are:
brainly.com/question/2193811
Answer:
Step-by-step explanation:
<h2>
<em><u>First</u></em><em><u> </u></em><em><u>case</u></em><em><u>:</u></em></h2>
Sides of a square = 3 cm
Therefore, area of the square = <em>side × side</em>
= 3cm × 3cm
<h2>
<em><u>Second</u></em><em><u> </u></em><em><u>c</u></em><em><u>ase</u></em><em><u>:</u></em></h2>
Radius of the circle = 4cm
Therefore, area of the circle
<h2><em><u>Last</u></em><em><u> </u></em><em><u>case</u></em><em><u>:</u></em></h2>
Area of the shaded region
= <em>Area</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>circle</em><em> </em><em>-</em><em> </em><em>Area</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>square</em><em> </em>