One minus the quotient of one and a number x.

Which expression is equivalent to -8? A=-2^-3 B=(-1/2)^-3 C=(1/2)^-3 D=2^-3

sladkih [1.3K]

Answer:

The answer is option B.

Step-by-step explanation:

$( - \frac{1}{2} ) ^{ - 3} = ( - 2) ^{3} = - 8$

Hope this helps you

4 0

3 years ago

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A box of Munchkins contains chocolate and glazed donut holes. If Jacob ate 2 chocolate

neonofarm [45]

Answer:

24 munchkins.

Step-by-step explanation:

Let C be the number of chocolate and D be number of glazed donut holes in the original box.

We are told if Jacob ate 2 chocolate munchkins, then 1/11 of the remaining Munchkins would be chocolate. We can represent this information as:

$C-2=\frac{1}{11}*(C+D-2)...(1)$

We are also told if he instead added 4 glazed Munchkins to the original box, 1/7 of the Munchkins would be chocolate. We can represent this information as:

$C=\frac{1}{7}*(C+D+4)...(2)$

Upon substituting C's value from equation (2) in equation (1) we will get,

$\frac{1}{7}*(C+D+4)-2=\frac{1}{11}*(C+D-2)$

Let us have a common denominator on right side of equation.

$\frac{1}{7}*(C+D+4)-\frac{7*2}{7}=\frac{1}{11}*(C+D-2)$

$\frac{C+D+4-14}{7}=\frac{1}{11}*(C+D-2)$

Multiplying both sides of our equation by 7, we will get,

$7*\frac{C+D-10}{7}=7*\frac{1}{11}*(C+D-2)$

$C+D-10=\frac{7}{11}*(C+D-2)$

Multiplying both sides of our equation by 11, we will get,

$11*(C+D-10)=11*\frac{7}{11}*(C+D-2)$

$11*(C+D-10)=7*(C+D-2)$

$11C+11D-110=7C+7D-14$

$11C-7C+11D-7D=-14+110$

$4C+4D=96$

$4(C+D)=96$

$(C+D)=\frac{96}{4}$

$(C+D)=24$

Therefore, the total number of Munchkins in original box is 24.

3 0

3 years ago

Please help me with this worksheet !! (Math ) I WILL GIVE BRAINLIEST TO right answers

omeli [17]

C=pi*d

=22/7*7

=22

22 is the circumference of first circle

6 0

3 years ago

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Explain how the commutative property of addition,the Associative property of addition and mental math can help you find 75.2+(57

4vir4ik [10]

Answer: The sum of 75.2+(57.376+24.8) is 157.376.

Explanation:

The commutative property of addition states that,

$a+b=b+a$

The associative property of addition states that,

$a+(b+c)=(a+b)+a$

The given expression is 75.2+(57.376+24.8).

First use commutative property of addition in the parenthesis.

$75.2+(57.376+24.8)=75.2+(24.8+57.376)$

Now use associative property of addition.

$75.2+(24.8+57.376)=(75.2+24.8)+57.376$

Now simplify the expression,

$(75.2+24.8)+57.376=100+57.376$

$(75.2+24.8)+57.376=157.376$

Therefore, the sum of 75.2+(57.376+24.8) is 157.376.

7 0

3 years ago

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Which of the following is the quotient of b and a?

vlabodo [156]

$\bf 19^{\frac{7}{4}}\cdot \sqrt[a]{19^b}=19^{\frac{5}{2}}\sqrt{19}\\\\
-----------------------------\\\\
a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
-----------------------------\\\\
thus\qquad 19^{\frac{7}{4}}\cdot 19^{\frac{b}{a}}=19^{\frac{5}{2}}\cdot 19^{\frac{1}{2}}\implies 19^{\frac{7}{4}+\frac{b}{a}}=19^{\frac{5}{2}+\frac{1}{2}}
\\\\\\
$

$\bf 19^{\frac{7}{4}+\frac{b}{a}}=19^{\frac{6}{2}}\implies 19^{\frac{7}{4}+\frac{b}{a}}=19^3\impliedby 
\begin{array}{llll}
\textit{same base, thus}\\
\textit{exponents must be the same}
\end{array}
\\\\\\
\cfrac{7}{4}+\cfrac{b}{a}=3\implies \cfrac{b}{a}=3-\cfrac{7}{4}$

5 0

3 years ago