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3 years ago

What do you think would be the most challenging part of investigating a fire or explosion crime scene? Why?

Chemistry

1 answer:

Lena [83]3 years ago

7 0

Answer:

I think finding the source of the fire would be the most difficult aspect seeing as though the fire would have burned any evidence

Explanation:

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what is the half life isotope if after 21 days you have 31.25 g remaining from a 250.0 g starting sample size?

alexgriva [62]

250 --> 125 --> 62.5 --> 31.25

each arrow equals one half life, so 3 half lives

14 days/ 3 half lives =

4.67 days = half life

3 0

3 years ago

Match each element with the element that is most similar to it. If you don’t know the answer, use this periodic table to help yo

yan [13]

Answer:

Lithium - Potassium

Carbon - Silicon

Fluorine - Bromine

Oxygen - Sulfur

Explanation:

I hope this helps!! :3

5 0

3 years ago

How many kilograms of solvent would contain 0.43 mol of CaO in a 2.5 molality solution

dalvyx [7]

<h3>Answer:</h3>

0.024 kg CaO

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Aqueous Solutions</u>

Molarity = moles of solute / liters of solution

<u>Atomic Structure</u>

Reading a Periodic Tables
Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

0.41 mol CaO

2.5 M Solution

<u>Step 2: Identify Conversions</u>

1000 g = 1 kg

Molar Mass of Ca - 40.08 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CaO - 40.08 + 16.00 = 56.08 g/mol

<u>Step 3: Convert</u>

Set up: $\displaystyle 0.43 \ mol \ CaO(\frac{56.08 \ g \ Cao}{1 \ mol \ CaO})(\frac{1 \ kg \ CaO}{1000 \ g \ CaO})$
Multiply: $\displaystyle 0.024114 \ kg \ CaO$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs as our lowest.</em>

0.024114 kg CaO ≈ 0.024 kg CaO

4 0

3 years ago

Read 2 more answers

What is the density of a cube that has a mass of 25 g in a volume of 125 cm 3

GalinKa [24]

<span>The density of an object is defined to be its mass divided by the volume it occupies. For this problem, the mass of the cube was given to be 25 g while its volume is 125 cm</span>³. Thus, we simply divide 25 g by 125 cm³ to get the object’s density. We then calculate that the cube has a density of 0.2 g/ cm³.

3 0

3 years ago

There are four major methods of purification in the chemistry laboratory. Which of the given techniques is not one of the four m

RideAnS [48]

Answer:

Sublimation

Explanation:

Sublimation is when a substance goes from a solid to a gas, without going through a liquid phase. This is not a method for separation and purification.

6 0

3 years ago