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Snowcat [4.5K]
3 years ago
11

(Physical or chemical)Properties describe matter

Chemistry
1 answer:
ss7ja [257]3 years ago
3 0

Answer:

All properties of matter are either physical or chemical properties and physical properties are either intensive or extensive. ... Physical properties can be measured without changing a substance's chemical identity. Chemical properties can be measured only by changing a substance's chemical identity.

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When (R)-6-bromo-2,6-dimethylnonane is dissolved in CH3OH, nucleophilic substitution yields an optically inactive solution. When
3241004551 [841]

Answer:

See explanation

Explanation:

The nucleophile here is CH3OH. We know that CH3OH is a good nucleophile that promotes SN2 reanction. However, (R)-6-bromo-2,6-dimethylnonane is a tertiary alkyl halide so the reaction proceeds by SN1 mechanism. This means that a racemic mixture is obtained at the end of the reaction because the attack occurs at the stereogenic carbon atom (6R) hence the product is optically inactive.

On the other hand, when (5R)-2-bromo-2,5-dimethylnonane is reacted with CH3OH, an optically active product is obtained because; though a tertiary alkyl halide and reaction occurs by SN1 mechanism, the attack does not occur at the stereogenic carbon atom (5R). Therefore, an optically active product is obtained in this case.

7 0
3 years ago
Please help me. ? :)
BaLLatris [955]

Answers and explanation:

To answer these questions you use a periodic table.

A is In because it has 49 protons and In is element number 49.

B is 27 because Co is element number 27.

C is 73 because Ta is element number 73.

D is 49 because the number of electrons in an atoms is always equal to the number of protons.

E is 56 because the atomic number of Ba is 56.

F is 54 because 56 - 54 = 2. The charge is equal to the number of protons minus the number of electrons.

G is 66. The number of neutrons is equal to the atomic mass minus the number of protons. 115 - 49 = 66.

H is 108 because 181 - 73 = 108.

I is 32. The atomic mass of an element is equal to the amount of protons plus the amount of neutrons. So 16 + 16 = 32.

3 0
4 years ago
Which type of isomers are o-xylene, m-xylene, and p-
mojhsa [17]

The  o-xylene, m-xylene, and p-Xylene are constitutional isomers. The correct option is D.

<h3>What are isomers?</h3>

Isomers are the elements or polyatomic elements that have similar molecular formula.

All options are attached here:

A.optical isomers

B.structural isomers

C.geometric isomers

D.constitutional isomers

Thus, the correct option is D.constitutional isomers.

Learn more about isomers

brainly.com/question/13422357

#SPJ1

4 0
2 years ago
Which of the following is an anion?Al3+ Mg2+ O2– H Save
JulijaS [17]
An anion is an ion with a negative charge. The minus sign, when attached to the end of an ionic compound, indicates that this has a negative charge, while a plus sign indicates a positive charge. 

O2- is the only compound listed that satisfied this. It is the anion.
Answer is 02-
5 0
3 years ago
Can send me the answer plzzz
Len [333]

Answer: In balancing any chemical equations, the number of atoms of each elements on the reactant side is equals to the number of atoms of the elements on the product side.

Explanation:

Balanced Chemical equations are those equations that has the equal number of atoms of elements on both the reactants and the product sides. To ensure that the chemical equations are correctly balanced the following steps should be observed.

--> identify the elements on the reactant side and on the product side

--> identify the number of atoms of each elements.

--> multiply the number of atoms with the number that will give you a coefficient that will make both the reactant and product sides equal.

--> place the new numbers infront of the elements or compounds.

--> A final check is done to know if the equation is balanced.

From the above steps, the balanced equation of the above questions are listed below:

1.) AlBr3 + 3K ---> 3KBr + Al

2.) FeO + PdF2 --> FeF2 + PdO

3.) P4 + 6Br2 --> 4PBr3

4.) 2LiCl + Br2 --> 2LiBr + Cl2

5.) PbBr2 + 2HCl --> 2HBr + PbCl2

6.) 2CoBr3 + 3CaSO4 --> 3CaBr2 + Co2(SO4)3

7.) 2Na3P + 3CaF2 --> 6NaF + Ca3P2

8.) 2Mn + 6HI --> 3H2 + 2MnI3

9.) Li3PO4 + 3NaBr --> Na3PO4 + 3LiBr

10.) CaF2 + Li2SO4 --> CaSO4 + 2LiF

11.) 2HBr + Mg(OH)2 --> MgBr2 + 2H2O

12.) 2LiNO3 + CaBr2 --> Ca(NO3)2 + 2LiBr

13.) AgNO3 + Li --> LiNO3 +Ag

14.) Si(OH)4 + 4NaBr --> SiBr4 + 4NaOH

15.) 2NaCN + CuCO3 --> Na2CO3 + Cu(CN)2

16.) 2NH3 + H2SO4 --> (NH4)2SO4

5 0
3 years ago
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