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hichkok12 [17]
4 years ago
7

Which equation describes the cosines function for right triangle?

Physics
1 answer:
Bogdan [553]4 years ago
8 0

Answer:a

Explanation:

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malfutka [58]
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3 years ago
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Calculate the p.e. of a 5 kg mass when it is (i) 3 m, (ii) 6 m, above the ground. (g = 10 N/kg)​
Mashcka [7]

Explanation:

P.E=MGH

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4 0
3 years ago
two teams are playing tug of war. team a pulls to the right with a force of 450n .team b pulls to the left with a force of 415 n
Alex_Xolod [135]

Explanation:

It is given that, two teams are playing tug of war.

Force applied by Team A, F_A=450\ N

Force applied by Team B, F_B=415\ N

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F_{net}=F_A-F_B

F_{net}=450-415

F_{net}=35\ N

So, the net force acting on the rope is 35 N and it is acting toward right. Hence, this is the required solution.

4 0
3 years ago
Light of wavelength λ travels through a medium with an index of refraction n1before striking a thin film with an index of refrac
ra1l [238]

Answer:

option C

Explanation:

The correct answer is option C

A light that transmits through n₂ travels t distance before reflection off the n₁ medium and again travels distance t before reaching the point from where it entered n₂  medium. Hence it travels 2 t distance more than the light that is reflected off n₂.

It( light entering n₂) also travels an additional distance equal to, half of the wavelength, when reflected off n₁ ( as n₁ is greater than n₂).  

Wavelength in n₂ is = \dfrac{\lambda}{n_2}  

Hence, path length difference = 2t +\dfrac{\lambda}{2 n_2}

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3 years ago
A small rock with mass 0.20 kg is released from rest at point A, which is at the top edge of a large, hemispherical bowl with ra
abruzzese [7]

Answer:

0(zero)

Explanation:

Given that m=0.20kg, radius of the bowl,R=050m and that the mass slides from point A to B.

-Since the normal force is perpendicular to the displacement at every point of the motion,then work  done by the normal force is zero.

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3 years ago
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