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hichkok12 [17]
3 years ago
7

Which equation describes the cosines function for right triangle?

Physics
1 answer:
Bogdan [553]3 years ago
8 0

Answer:a

Explanation:

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Before digital filmmaking, what tool was used to control the speed of movement on the screen after filming?
nikitadnepr [17]

Answer:

The appropriate response is "Optical printer ".

Explanation:

  • A photographic printer used mostly for optical aberrations, comprised simply of either a camera that captures the frame to expand, minimize, deform, respectively. through magnifying lenses.
  • A projector that always, as distinct from some kind of touch printer, transferred the image to something like the printing supply.
4 0
3 years ago
The earth’s magnetic field is located in the _____.
Natali [406]
Near Greenland in the northern hemisphere  <span />
7 0
3 years ago
Are photons causing the electrons to flow off of the target? ( the target is calcium)
Sliva [168]

Answer:

The energy lost by the atoms is given off as an electromagnetic wave. ... even if it's not very intense, will always cause electrons to be emitted.

Explanation:

5 0
3 years ago
Suppose that you are swimming in a river while a friend watches from the shore. In calm water, you swim at a speed of 1.25 m/s .
aliya0001 [1]

Answer: The observing friend will the swimmer moving at a speed of 0.25 m/s.

Explanation:

  • Let <em>S</em> be the speed of the swimmer, given as 1.25 m/s
  • Let S_{0} be the speed of the river's current given as 1.00 m/s.

  • Note that this speed is the magnitude of the velocity which is a vector quantity.
  • The direction of the swimmer is upstream.

Hence the resultant velocity is given as, S_{R} = S — S 0S_{0}

S_{R} = 1.25 — 1

S_{R} = 0.25 m/s.

Therefore, the observing friend will see the swimmer moving at a speed of 0.25 m/s due to resistance produced by the current of the river.

6 0
3 years ago
The velocity of a 48.0 g shell leaving a 2.95 kg rifle is 391. m/s. What is the recoil velocity of the rifle?
Monica [59]

Hi there!

\large\boxed{  -6.36m/s}

Use the equation:

v_{2} = -\frac{m_{1}}{m_{2}} v_{1}

Where m2 and v2 deal with the larger object, and m1 and v1 with the smaller object. Plug in the given values:

v2 = ?

m1 = 0.048 kg (converted)

m2 = 2.95

v1 = 391

v_{2} = -\frac{0.048}{2.95} *391

v_{2} = -6.36m/s

8 0
3 years ago
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