Answer:
θ = 4.716 10⁻⁶ rad
Explanation:
In order for the releases to be considered separate, they must meet the Rayleigh criterion that establishes that the maximum diffraction of one star must coincide with the first minimum of the diffraction pattern of the second star.
We use the diffraction equation for a slit
a sin θ = m λ
The minimum occurs at m = 1
sin θ = λ / a
Since the angles in these systems are very small, we can approximate the sine to its angle in radians
θ = λ / a
The telescope has a circular aperture whereby polar cords should be used, which introduces a constant number
θ = 1.22 λ / a
Let's calculate
θ = 1.22 518 10⁻⁹ / 13.4 10⁻²
θ = 4.716 10⁻⁶ rad
The inductance of several inductors in series is the sum of all the individuals ... just like for resistors.
a). With 1.05H and 2.07H in series, the equivalent total inductance is <em>3.12H</em> , provided the inductors can't influence each other with their magnetic fields.
b). If you had 30 identical inductors in series, each with inductance of 3.03H, AND none of them could influence any other ones with their magnetic fields, their combined equivalent inductance would be
(30) · (3.03H) = <em>90.9 H</em> .
The formula for mass you can find from the density equation. Multiply the volume by both sides of the equation.
density = mass/volume
volume*density = mass
And there you are :)
